[英]Router.use() requires middleware function but got a undefined at function use
[英]Router.use() requires a middleware function but got a undefined
我的 index.js 中有这段代码
...
import userRoutes from './src/routes/userRoutes';
import invoicesRoutes from './src/routes/invoicesRoutes';
import authMiddleware from "./src/middlewares/authMiddleware";
...
const app = express();
...
app.use('/user', authMiddleware, userRoutes(app));
app.use('/invoices', authMiddleware, invoicesRoutes(app));
我的身份验证中间件
const authMiddleware = (req, res, next) => {
if (req.headers && req.headers.authorization && req.headers.authorization.split(' ')[0] === 'JWT') {
console.log(req.headers.authorization.split(' ')[0]);
next();
} else {
console.log('else');
next();
}
};
export default authMiddleware;
和我的路线之一:
import { register, login } from '../controllers/authController';
const userRoutes = (app) => {
app.route('/user/signup')
.post(register);
app.route('/user/login')
.post(login);
};
export default userRoutes;
我收到一个错误:
throw new TypeError('Router.use() 需要一个中间件函数,但得到了一个 ' + gettype(fn)) ^
类型错误:Router.use() 需要一个中间件函数,但有一个未定义的
怎么了?
您将路由初始化作为中间件功能app.use('/user', authMiddleware, userRoutes(app));
在这行代码中, userRoutes(app)
应该返回的是function(req,res[,next]){}
它应该是这样的
app.use('/user', authMiddleware, (req, res, next) => {
userRoutes(app);
next()
})
而你所做的是
app.use('/user', authMiddleware, (app) => {
app.route('/user/signup').post(register);
app.route('/user/login').post(login);
})
那是错误的
这里似乎有一些不好的逻辑,因为据我所知,您将不得不调用http://localhost/user
来初始化路由,并且由于包含 express 的中间件而无法正常工作。
再次根据我的理解,您正在尝试做的事情应该看起来更像这样
...
import userRoutes from './src/routes/userRoutes';
import invoicesRoutes from './src/routes/invoicesRoutes';
...
const app = express();
userRoutes(app);
invoicesRoutes(app);
和
import { register, login } from '../controllers/authController';
import authMiddleware from "./middleware";
const userRoutes = (app) => {
app.post('/user/signup', authMiddleware, register);
app.post('/user/login', authMiddleware, login);
};
export default userRoutes;
Express 已经提供了Router 类来分隔不同子模块中的路由,因此您可以导入userRoutes
模块而无需将app
变量传递给它,这是一个示例:
用户路由.js
import { register, login } from '../controllers/authController';
import express from 'express';
const router = express.Router();
router.route('/signup')
.post(register);
router.route('/login')
.post(login);
export default router;
索引.js
...
import userRoutes from './src/routes/userRoutes';
import invoicesRoutes from './src/routes/invoicesRoutes';
import authMiddleware from "./src/middlewares/authMiddleware";
...
const app = express();
...
app.use('/user', authMiddleware, userRoutes);
app.use('/invoices', authMiddleware, invoicesRoutes);
希望这可以帮助
检查所有 JavaScript 文件以确保没有遗漏以下行:
module.exports = router
在我的 route.js
我把它像这样module.exports = routes;
我打算做的是导出路由,像下面这样更改后,我的错误消失了module.exports = {routes};
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