postgres按公共ID在多行数组中分组

Question

我有一张这样的桌子：

{
"type": "FeatureCollection",
"name": "test",
"crs": { "type": "name", "properties": { "name": "urn:ogc:def:crs:OGC:1.3:CRS84" } },
"features": [
{ "type": "Feature", "properties": { "final_zone": "ECZ", "id": 20753, "ids": "{22210,10959,22209,22213}", "sub": "{ECZECSZ,NULL,ECZECSZ,ECZECSZ}" }, "geometry": null },
{ "type": "Feature", "properties": { "final_zone": "Protection", "id": 6516, "ids": "{24920,24943}", "sub": "{NULL,NULL}" }, "geometry": null },
{ "type": "Feature", "properties": { "final_zone": "Protection", "id": 6524, "ids": "{24912,24920,24943,24971,24944}", "sub": "{NULL,NULL,NULL,NULL,NULL}" }, "geometry": null },
{ "type": "Feature", "properties": { "final_zone": "Protection", "id": 6528, "ids": "{24943,24958,24944}", "sub": "{NULL,NULL,NULL}" }, "geometry": null },
{ "type": "Feature", "properties": { "final_zone": "Protection", "id": 6610, "ids": "{24943,24971}", "sub": "{NULL,NULL}" }, "geometry": null },
{ "type": "Feature", "properties": { "final_zone": "Protection", "id": 6781, "ids": "{24912,24906,24943}", "sub": "{NULL,NULL,NULL}" }, "geometry": null }
]
}

在此特定实例中，所有5行中都存在24943。 我该如何折叠这样的桌子？ 并将阵列汇总为1个平滑阵列。

请记住，还有成千上万的其他行，所以我不要一个庞大的组。 我只想将ids数组中具有相同公共ID的行折叠起来

我可以做这个

with abid as(
select regexp_replace(id,'[{}]','','gi')::int id from(
    select unnest(ids) id from(
        select string_to_array(ids,',') ids from conflict.test
        )t
    )t2
),
abid2 as(select ids::int[] id from conflict.test
    )
select t2.*,t.* from abid t,abid2 t2 where t.id =any(t2.id)

只是为了给更多的范围，下面的棕色中间部分的ID为24943

Answer 1

不清楚您想要的结果，如果您只是想统一数组，请尝试以下操作：

with tmp as (
select unnest(ids) ids
from your_table_name
group by unnest(ids)
)
select x.final_zone, x.id, array_agg(t.ids), x.sub, x.polys
from tmp t
cross join your_table_name x
group by x.final_zone, x.id, x.sub, x.polys;