[英]Pulling in data from MySQL and displaying in table using table id in php?
[英]Displaying data from a mysql table using php
由于某种原因,这个php块不断返回此错误,我无法弄清楚原因; 我已经以多种样式和范例列出了相同的代码,但它不断返回错误
mysqli_fetch_assoc() expects parameter 1 to be mysqli_result
但是,当我更改代码以利用mysqli_result函数时,php表示未定义。
PHP块:
global $connection;
$query ="SELECT * FROM Members AND EXISTS (SELECT * FROM Lead);";
$result = mysqli_query($connection, $query);
$row = mysqli_fetch_assoc($result);
while($row){
echo "<li>".$row['FIRST_NAME']."</li>";
}
1.Replace AND
用WHERE
里面查询
2. $row = mysqli_fetch_assoc($result);
在while()
内部
像下面这样:
global $connection;
$query ="SELECT * FROM Members WHERE EXISTS (SELECT * FROM Lead);";
$result = mysqli_query($connection, $query);
while($row = mysqli_fetch_assoc($result)){
echo "<li>".$row['FIRST_NAME']."</li>";
}
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