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C编程为什么不起作用?

[英]C-Programming.Why Doesn't This Work?

以下程序应搜索多维数组。 当我输入town一词作为输入时,它应该返回Track 1: Newark,Newark-A Wonderful Town但我没有收到任何输出(什么也没有发生),有什么解决办法?

我正在编写《 Head First C》书。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

/* Run this program using the console pauser
or add your own _getch, system("pause") or input loop */

char tracks[][80]={
        "I Left My Heart In Harvard Med School",
        "Newark,Newark-A Wonderful Town",
        "From Here to Maternity",
        "The Girl From Iwo Jima",
    };


void find_track(char search_for[]){
    int i;
    for (i=0;i<=4;i++){
        if(strstr(tracks[i],search_for)){

            printf("Track %i:'%s' \n",i,tracks[i]);

    }
    }
}

int main(int argc, char *argv[]) {
    char search_for[80];
    printf("Search for: ");
    fgets(search_for,80,stdin);
    find_track(search_for);

    return 0;
}

如上所述, fgets从您的输入中存储换行符,它将不匹配。 只要您在标题中匹配测试的大小写,从该search_for字符串中search_for最后一个字符就可以使它工作。 另外,请注意,您的for循环应使i < 4而不是i <= 4

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */
char tracks[][80]={
        "I Left My Heart In Harvard Med School",
        "Newark,Newark-A Wonderful Town",
        "From Here to Maternity",
        "The Girl From Iwo Jima",
    };


void find_track(char search_for[]){
    int i;
    for (i=0;i<4;i++){
        if(strstr(tracks[i], search_for)){
          printf("Track %i:'%s' \n",i,tracks[i]);
        }
    }
}

int main(int argc, char *argv[]) {
    char search_for[80];
    printf("Search for: ");
    fgets(search_for,80,stdin);
    search_for[strlen(search_for)-1] = '\0'; // truncate input
    find_track(search_for);

    return 0;
}

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