![](/img/trans.png)
[英]Error like this: Google PHP API Client requires the CURL PHP extension
[英]cURL PHP API client
我正在尝试访问以下API:
https://image.ibb.co/nabzZw/segmentify_api.jpg
我的代码如下,但不起作用:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "https://panel-api.segmentify.com/getToken");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "{\"username\":\"XXXXX\",\"password\":\"YYYYYYY\"};");
curl_setopt($ch, CURLOPT_POST, 1);
$headers = array();
$headers[] = "Content-Type: application/json; charset=UTF-8";
$headers[] = "Accept: application/json, text/javascript, */*; q=0.01";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
$result = curl_exec($ch);
if (curl_errno($ch)) {
echo 'Error:' . curl_error($ch);
}
curl_close ($ch);
解决方案可能是什么?
您发送的是无效的json,
替换curl_setopt($ch, CURLOPT_POSTFIELDS, "{\\"username\\":\\"XXXXX\\",\\"password\\":\\"YYYYYYY\\"};");
同
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode(array(
'username'=>'XXXXX',
'password'=>'YYYYYYYYY'
)));
而且不会再发生了 (但您真正的错误是最后一个分号,json不允许使用。虽然是合法的javascript。但是,让PHP为您生成json比手工制作json字符串要安全得多,因为您刚经历过拳头。)
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