Javascript：从多个具有相同名称的变量中获取最后结果

Question

在尝试修复以前的程序员的错误时，我发现了一个if函数，该函数提供相同的变量多个信息，从而使我们的链接混乱。

 // This piece of script, when there is multiple 'x' selections: if (x == 0){ var searchBrand = "" } else if (x == 1) { var searchBrand = "one" } else if (x == 2) { var searchBrand = "two" } else if (x == 3) { var searchBrand = "three" } else if (x == 4) { var searchBrand = "four" } else if (x == 5) { var searchBrand = "five" } // and processed via: var newurl = $(this).attr('href').replace('/search?q=', '/search?q=' + searchBrand + '%20'+ '%20'+ '%20'); // output in reverse order selected: /search?q=four%20%20%20two%20%20%20five%20%20%20 

我尝试过类似的方法：

 else if (x == 3) { var sB = { searchBrand: three; } } var newurl = $(this).attr('href').replace('/search?q=', '/search?q=' + sB.searchBrand + '%20') 

和别的。

我要实现的是仅在newurl变量中获取最后选择的x的searchBrand值。

Answer 1

如果是ladder，则将searchBrand变量声明为其他变量。

var searchBrand = "";

// This piece of script, when there is multiple 'x' selections:
if (x == 0){
   searchBrand = "";
}
else if (x == 1) {
   searchBrand = "one";
}
else if (x == 2) {
   searchBrand = "two";
 }
else if (x == 3) {
   searchBrand = "three";
}
else if (x == 4) {
   searchBrand = "four";
}
else if (x == 5) {
   searchBrand = "five";
}

Answer 2

在下面使用这样的数组

let searchBrand = ['','one','two','three','four','five']
var newurl = $(this).attr('href').replace('/search?q=', '/search?q=' + searchBrand[x] + '%20'+ '%20'+ '%20');

let queryParameter = ''
while(numberOfIterations){
    queryParameter = queryParameter+searchBrand[x]+'%20%20%20'
} //numberOfIterations is the number of times the value x is input

另外，我认为这个问题的框架并不完善。 那么，您可以更好地重新构架吗？