[英]Append an argument to a variable in a LESS mixin
这是我的代码:
@color-level-1: #99FFDD;
@color-level-2: #4484F6;
@color-level-3: #E91E63;
@color-level-4: #E99D1E;
@color-level-5: #D51EE9;
.some-color(@i) {
+ .some-class-name {
background-color: @color-level-@i;
}
}
.another-class-name {
.some-color(3);
}
试图完成的工作是在使用mixin时获得以下输出:
.another-class-name + .some-class-name {
background-color: #E91E63;
}
不幸的是,它不起作用。 我得到的输出是:
.another-class-name + .some-class-name {
background-color: 3;
}
我已经尝试过转义,但这也无济于事。 有人知道如何使其工作吗?
有两种方法可以做到这一点。 第一个是:
@color-level-1: #99FFDD; @color-level-2: #4484F6; @color-level-3: #E91E63; @color-level-4: #E99D1E; @color-level-5: #D51EE9; .some-color(@i) { + .some-class-name { background-color: ~"@{color-level-@{i}}"; } } .another-class-name { .some-color(3); }
第二个是:
@color-level-1: #99FFDD; @color-level-2: #4484F6; @color-level-3: #E91E63; @color-level-4: #E99D1E; @color-level-5: #D51EE9; .some-color(@i) { + .some-class-name { @color-name: "color-level-@{i}"; background-color: @@color-name; } } .another-class-name { .some-color(3); }
这些都返回:
.another-class-name + .some-class-name { background-color: #E91E63; }
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