[英]how to show from certain date onwards
您可以为查询添加条件日期和限制:
SELECT
EmployeeID,[Date], ShiftType, Shift_Description
FROM
Roster r inner join ShiftType s on r.ShiftType = s.ShiftID
WHERE EmployeeID = 123123 AND Date > '2018-01-11'
ORDER BY [Date] ASC
LIMIT 7;
对于MySQL
使用Limit
:
SELECT
EmployeeID,[Date], ShiftType, Shift_Description
FROM
Roster r inner join ShiftType s on r.ShiftType = s.ShiftID
WHERE EmployeeID = 123123 AND Date >= '2018-01-11'
ORDER BY [Date] ASC
LIMIT 7;
对于SQL Server
使用TOP
:
SELECT Top 7
EmployeeID,[Date], ShiftType, Shift_Description
FROM
Roster r inner join ShiftType s on r.ShiftType = s.ShiftID
WHERE EmployeeID = 123123 AND Date >= '2018-01-11'
ORDER BY [Date] ASC;
您没有指定数据库,但从屏幕截图和查询语法来看,它似乎是SQL Server,因此我将在此基础上进行回答。
添加日期条件后,可以使用TOP
语句获取前7条记录:
SELECT TOP 7
EmployeeID, [Date], ShiftType, Shift_Description
FROM Roster r
INNER JOIN ShiftType s ON r.ShiftType = s.ShiftID
WHERE EmployeeID = 123123
AND [DATE] >= '2018-01-11'
ORDER BY [Date] ASC;
您也可以使用DATEDIFF()
函数比较日期。 在此查询中,它至少在2018年1月10日之后的一天开始:
SELECT TOP 7
EmployeeID, [Date], ShiftType, Shift_Description
FROM Roster r
INNER JOIN ShiftType s ON r.ShiftType = s.ShiftID
WHERE EmployeeID = 123123
AND DATEDIFF(DAY, '2018-01-10', [DATE]) > 0
ORDER BY [Date] ASC;
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