convert（void *）to（SInt16 *）to Swift

Question

我正在尝试将以下内容从Objective-C转换为Swift：

-(int)fillBuffer:(void *)buffer {
  SInt16* p = (SInt16 *)buffer;

  // ...

  p[33] = 0
}

我已经明白(void *)映射到UnsafeMutableRawPointer? 输入Swift。

但是，我错过了将其转换为可以进行下标操作的步骤。

到目前为止，我有这个：

func fill(buffer: UnsafeMutableRawPointer!) -> Int {
  buffer[33] = 0
}

寻求反馈和建议。 提前致谢！

Answer 1

将void指针强制转换为类型指针

SInt16* p = (SInt16 *)buffer;

在使用assumingMemoryBound() Swift中完成：

func fillBuffer(_ buffer: UnsafeMutableRawPointer) -> Int {
    let p = buffer.assumingMemoryBound(to: Int16.self)
    // ...
    p[33] = 0
    return 0
}

测试代码：

var i16Array = Array(repeating: Int16(99), count: 40)
print(i16Array[33]) // 99
_ = fillBuffer(&i16Array) // passes a pointer to the element storage to the function
print(i16Array[33]) // 0