[英]Printing 10 random questions in JAVA
我的任务是用Java创建一个测验程序,该程序要求用户找到10种加法/减法问题形式(a + b)或(a-b)= c的答案,其中“ a”和“ b”是随机数。 我能够完成第一部分,其中随机生成“ a”和“ b”,并告知用户其答案是否正确。 我被困在如何产生10次此问题以及如何随机选择运算符是“ +”还是“-”的问题上。 下面是我到目前为止的代码:
import java.util.Scanner;
import java.util.Random;
public class LetsSee{
public static void main(String [] args){
Scanner keyboard = new Scanner(System.in);
int sum = 0;
int userAnswer ;
int check ;
// Random number generating
Random generator = new Random();
int N1 = generator.nextInt(100);
int N2 = generator.nextInt(N1);
System.out.println(" What is the answer to " + N1 + " + " + N2 + " = " );
userAnswer = new Scanner(System.in).nextInt();
// Display if its correct or not
check = N1 + N2;
if(userAnswer == check){
System.out.println("You are correct!");
}
else{
System.out.println(" Sorry, the correct answer is : " + check);
}
}
}
帮助将不胜感激。 谢谢 !
让我知道是否有帮助。 我只是添加了一个for循环,要求用户输入10次,然后根据随机int是偶数还是奇数构建+/-。
import java.util.Scanner;
import java.util.Random;
public class HelloWorld{
public static void main(String [] args){
Scanner keyboard = new Scanner(System.in);
int sum = 0;
int userAnswer ;
int check ;
// Random number generating
// Ask the user for input 10 times
for (int i = 0; i < 10; i++) {
Random generator = new Random();
int N1 = generator.nextInt(100);
int N2 = generator.nextInt(N1);
int N3 = generator.nextInt(2);
// if N3 is even use plus, if odd use minus
Boolean plus = N3 % 2 == 0;
// Set a string to either "+" or "-" depending on the value of plus
String plusMinus = plus? "+" : "-";
System.out.println(" What is the answer to " + N1 + plusMinus + N2 + " = " );
userAnswer = new Scanner(System.in).nextInt();
// Display if its correct or not
// Set the answer depending on the value of plus.
check = plus? N1 + N2 : N1 - N2;
if(userAnswer == check){
System.out.println("You are correct!");
}
else{
System.out.println(" Sorry, the correct answer is : " + check);
}
}
}
}
所以我想出了一个快速的解决方案,看起来像这样
Random generator = new Random();
int var1 = generator.nextInt(100);
int var2 = generator.nextInt(100);
int choice = generator.nextInt(3);
switch (choice){
case 0:
System.out.println(var1 + " + " + var2);
break;
case 1:
System.out.println(var1 + " - " + var2);
break;
case 2:
System.out.println(var1 + " * " + var2);
break;
case 3:
System.out.println(var1 + " / " + var2);
break;
}
这只是一个粗略的解决方案,没什么花哨的,但希望能使您对所要查找的内容有所了解。
您需要从4个运算符中选择一个,所以我从0-3中随机选择了一个数字以获得一个随机运算符,然后我们可以在开关中使用它来基于我们的2个随机数生成问题
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