无法通过mysql数据库上的php创建帐户
[英]fail to create account via php on mysql database
问题描述
我无法通过自己创建的php在MySQL数据库上创建数据，以便能够在我正在制作的网站上创建帐户。我有以下php文件负责处理该过程（如下链接），我一直在寻找这些代码行达数小时之久，而我却无法找出问题出在哪里.....
signup.php
<?php
require 'db.php';
session_start();
?>
<!DOCTYPE html>
<html>
<head>
<title>AlojArt Reservas</title>
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<!-- Bootstrap -->
<link href="bootstrap/css/bootstrap.min.css" rel="stylesheet">
<!-- styles -->
<link href="css/styles.css" rel="stylesheet">
<!-- HTML5 Shim and Respond.js IE8 support of HTML5 elements and media queries -->
<!-- WARNING: Respond.js doesn't work if you view the page via file:// -->
<!--[if lt IE 9]>
<script src="https://oss.maxcdn.com/libs/html5shiv/3.7.0/html5shiv.js"></script>
<script src="https://oss.maxcdn.com/libs/respond.js/1.3.0/respond.min.js"></script>
<![endif]-->
</head>
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
if (isset($_POST['login'])) { //user logging in
require 'login.php';
}
elseif (isset($_POST['register'])) { //user registering
require 'register.php';
}
}
?>
<body class="login-bg">
<div class="header">
<div class="container">
<div class="row">
<div class="col-md-12">
<!-------------------- Logo -------------------->
<div class="logo">
<h1><a href="index.php">AlojArt Reservas</a></h1>
</div>
</div>
</div>
</div>
</div>
<div class="page-content container">
<div class="row">
<div class="col-md-4 col-md-offset-4">
<div class="login-wrapper">
<div id="register">
<div class="box">
<form action="signup.php" method="post" autocomplete="off">
<div class="content-wrap">
<h6>Criar conta</h6>
<input class="form-control" type="text" placeholder="Nome" name="nome_titular">
<input class="form-control" type="text" placeholder="Nome de utilizador " name="username">
<input class="form-control" type="password" placeholder="Palavra-passe" name="password">
<input class="form-control" type="email" placeholder="Endereço de e-mail" name="email">
<div class="action">
<button class="btn btn-primary btn-lg" name="register" />Criar conta</button>
</div>
</div>
</form>
</div>
</div>
<div class="already">
<div id="login">
<p>Já tem conta?</p>
<a href="index.php">Iniciar sessão</a>
</div>
</div>
</div>
</div>
</div>
</div>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://code.jquery.com/jquery.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script src="bootstrap/js/bootstrap.min.js"></script>
<script src="js/custom.js"></script>
</body>
</html>
register.php
<?php
require 'db.php';
session_start();
$_SESSION['nome_titular'] = $_POST['nome_titular'];
$_SESSION['username'] = $_POST['username'];
$_SESSION['password'] = $_POST['password'];
$_SESSION['email'] = $_POST['email'];
// Escape all $_POST variables to protect against SQL injections
$nome_titular = $mysqli->escape_string($_POST['nome_titular']);
$username = $mysqli->escape_string($_POST['username']);
$email = $mysqli->escape_string($_POST['email']);
$password = $mysqli->escape_string(password_hash($_POST['password'], PASSWORD_BCRYPT));
// Check if user with that email already exists
$result = $mysqli->query("SELECT * FROM Utilizador WHERE email='$email'") or die($mysqli->error());
// We know user email exists if the rows returned are more than 0
if ( $result->num_rows > 0 ) {
$_SESSION['message'] = 'O utilizador jรก existe!';
header("location: error.php");
}
else { // User doesn't already exist in a database, proceed...
$sql = "INSERT INTO Utilizador (nome_titular, username, email, password)"
. "VALUES ('$nome_titular','$username','$email','$password')";
// Add user to the database
if ( $mysqli->query($sql) ){
$_SESSION['logged_in'] = true;
header("location: dashboard.php");
}
else {
$_SESSION['message'] = "O registo falhou!";
header("location: error.php");
}
}
?>
编辑：添加了db.php
db.php
<?php
/* Database connection settings */
$host = 'CENSORED';
$user = 'CENSORED';
$pass = 'CENSORED';
$db = 'projeto2_dcw';
$mysqli = new mysqli($host,$user,$pass,$db) or die($mysqli->error);
?>
2 个解决方案
解决方案1
0 已采纳 2018-01-26 04:24:57
我看到VALUES之前没有空格' ' ，这将导致SQL失败。
将您的SQL更改为
$sql = "INSERT INTO Utilizador (nome_titular, username, email, password)"
. " VALUES ('$nome_titular','$username','$email','$password')";
如果仍然得到意外的结果，请输入以下代码以获取else错误并注释掉所有其他内容。
printf("Error: %s\n", $mysqli->error);
==更新==
“错误：键“ PRIMARY”的条目“ 0”重复”
它指的是违反primary key约束，换句话说，您试图插入新值0 ，该值已经存在于同一列中。 因为， primary key不允许重复。 它正在失败，并陷入else障碍。 要更正此问题，您需要确保没有具有primary key列的重复条目。
解决方案2
0 2018-01-26 04:27:37
我看到您的页面没有连接，这就是为什么它被重定向到error.php将您的数据库连接更改为此
<?php
$host = 'CENSORED';
$user = 'CENSORED';
$pass = 'CENSORED';
$db = 'projeto2_dcw';
$con = mysqli_connect("$host,$user,$pass,$db") or die($mysqli->error);
mysqli_select_db($con,"your db name");
?>
在表单更改按钮中<button type="submit" class="btn btn-primary btn-lg" name="register" />Criar
ALTER TABLE Your table name
ADD PRIMARY KEY (ID);
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