[英]Min Max Average Data input
仍然为此奋斗。 需要找到输入数据的最小值,最大值和平均值,并将其打印到外部数据文件中。 谁能在我的代码中发现问题。 它不会打印任何内容。
它需要读取一个包含以下内容的文件
min:1,2,3,4,5,6
max:1,2,3,4,5,6
avg:1,2,3,4,5,6
但需要以以下格式打印出来
The min of [1, 2, 3, 5, 6] is 1.
The max of [1, 2, 3, 5, 6] is 6.
The avg of [1, 2, 3, 5, 6] is 3.4.
public class Test {
public static void main(String[] args) throws IOException {
FileInputStream fi = new FileInputStream("F:\\Test\\file.txt");
FileOutputStream fo = new FileOutputStream("F:\\Test\\output.txt");
BufferedReader br = new BufferedReader(new InputStreamReader(fi));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(fo));
String strLine;
while ((strLine = br.readLine()) != null) {
String[] arr = strLine.split(" ");
String[] nos = arr[1].split(",");
Set<Integer> set = new HashSet<Integer>();
for(int i = 0; i<nos.length; i++){
int no = Integer.parseInt(nos[i]);
set.add(no);
}
TreeSet<Integer> sortedSet = new TreeSet<Integer>(set);
switch(arr[0]) {
case "Min:":
String msg1="The Min of [" +arr[1]+ "] is " +(Integer)sortedSet.first();
bw.write(msg1);
bw.newLine();
break;
case "Max:":
String msg2="The Max of [" +arr[1]+ "] is " +(Integer)sortedSet.last();
bw.write(msg2);
bw.newLine();
break;
case "Avg:":
Object[] noarray = sortedSet.toArray();
int noarraysize = noarray.length-1;
int sum=0;
for(int i=0;i<=noarraysize;i++) {
int no=Integer.valueOf(noarray[i].toString());
sum = sum + no;
if(i==noarraysize) {
String msg3="The Avg of [" +arr[1]+ "] is " +(double)sum/noarray.length;
bw.write(msg3);
bw.newLine();
}
}
break;
case "Sum:":
Object[] noarray1 = sortedSet.toArray();
int noarraysize1 = noarray1.length-1;
int sum1=0;
for(int i=0;i<=noarraysize1;i++) {
int no=Integer.valueOf(noarray1[i].toString());
sum1 = sum1 + no;
if(i==noarraysize1) {
String msg4="The Sum of [" +arr[1]+ "] is " +sum1;
bw.write(msg4);
bw.newLine();
}
}
break;
}
}
br.close();
bw.close();
}
}
如果我在代码主体之外添加了一条打印语句,则它可以工作,但是我输入的所有消息都不会从外部打印到文本文件中。
这行似乎是您的第一个问题:
String[] nos = arr[1].split(",");
arr
仅包含一个元素,因此您可以在数组范围之外进行访问(请记住数组的索引为0,因此第一个元素为arr [0])。
您在这里还有另一个问题:
int no = Integer.parseInt(nos[i]);
在尝试从输入解析一个int之前,您需要消耗输入的min:
部分。
Edit进行了一些其他更改,使之可以与您提供的输入一起使用:
public static void main(String[] args) throws IOException {
FileInputStream fi = new FileInputStream("file.txt");
FileOutputStream fo = new FileOutputStream("output.txt");
BufferedReader br = new BufferedReader(new InputStreamReader(fi));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(fo));
String strLine;
while ((strLine = br.readLine()) != null) {
String[] arr = strLine.split(":");
String[] nos = arr[1].split(",");
Set<Integer> set = new HashSet<Integer>();
for(int i = 0; i<nos.length; i++){
int no = Integer.parseInt(nos[i]);
set.add(no);
}
TreeSet<Integer> sortedSet = new TreeSet<Integer>(set);
switch(arr[0]) {
case "min":
String msg1="The Min of [" +arr[1]+ "] is " +(Integer)sortedSet.first();
bw.write(msg1);
bw.newLine();
break;
case "max":
String msg2="The Max of [" +arr[1]+ "] is " +(Integer)sortedSet.last();
bw.write(msg2);
bw.newLine();
break;
case "avg":
Object[] noarray = sortedSet.toArray();
int noarraysize = noarray.length-1;
int sum=0;
for(int i=0;i<=noarraysize;i++) {
int no=Integer.valueOf(noarray[i].toString());
sum = sum + no;
if(i==noarraysize) {
String msg3="The Avg of [" +arr[1]+ "] is " +(double)sum/noarray.length;
bw.write(msg3);
bw.newLine();
}
}
break;
case "sum":
Object[] noarray1 = sortedSet.toArray();
int noarraysize1 = noarray1.length-1;
int sum1=0;
for(int i=0;i<=noarraysize1;i++) {
int no=Integer.valueOf(noarray1[i].toString());
sum1 = sum1 + no;
if(i==noarraysize1) {
String msg4="The Sum of [" +arr[1]+ "] is " +sum1;
bw.write(msg4);
bw.newLine();
}
}
break;
}
}
br.close();
bw.close();
}
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