[英]How to merge 3 drop down menus to one?
我对角度很新,我有点陷入困境。 我有一个问题jsfiddle的示例
function HelloCntl($scope) {
$scope.selectname1={};
$scope.selectname2={};
$scope.selectname3={};
$scope.filter1 = function(item){
return (!($scope.selectname1&&$scope.selectname1.id)||item.id !=$scope.selectname1.id);
};
$scope.filter2 = function(item){
return (!($scope.selectname2&&$scope.selectname2.id)||item.id!=$scope.selectname2.id);
};
$scope.filter3 = function(item){
return (!($scope.selectname3&&$scope.selectname3.id)||item.id !=$scope.selectname3.id);
};
$scope.friends = [
{
id:1,name: 'John'},
{
id:2,name: 'Mary'},
{
id:3,name: 'Mike'},
{
id:4,name: 'Adam'},
{
id:5,name: 'Julie'}
];
}
<div ng:app>
<div ng-controller="HelloCntl">
<ul>
<li ng-repeat="friend in friends | filter:{name:'!Adam'}">
<span>{{friend.name}}</span>
</li>
</ul>
<select ng-model="selectname1"
ng-options="item as item.name for item in friends|filter:filter2|filter:filter3" ><option value="">- select - </option></select>
<div>{{selectname1}}</div>
<select ng-model="selectname2"
ng-options="item as item.name for item in friends|filter:filter1|filter:filter3" ><option value="">- select -</option></select>
<div>{{selectname2}}</div>
<select ng-model="selectname3" ng-options="item as item.name for item in friends|filter:filter1|filter:filter2" ><option value="">- select -</option></select>
<div>{{selectname3}}</div>
</div>
</div>
我试图在一个下拉菜单中实现此代码,而不是3个菜单。 每次单击都会显示所选选项。
我正在尝试的整体功能是创建一个包含项目的下拉菜单。 选择这些项目后,将使用删除按钮在下面打印其名称。 选择项目后,应自动从下拉列表中删除该项目,以使其无法进一步使用。 并且可以在下面进一步添加另一个项目(追加)
不幸的是,我似乎无法弄清楚如何让这个工作。 任何人都可以帮我解决这个问题吗?
我认为这是你所要求的全面实施。 您可以更改一些逻辑并适当调整我的示例:
<!DOCTYPE html> <html> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css"> <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script> <script srt="https://cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/2.5.0/ui-bootstrap.min.js"></script> <body> <div ng-app="myApp" ng-controller="HelloCntl"> <div ng-controller="HelloCntl"> <select ng-model="selected" ng-options="i as i.name for i in friends"></select> <button class="btn btn-danger" ng-click="delete(selected)">X</button> <div ng-show="selected" class="alert alert-info">Name: {{selected.name}} | ID: {{selected.id}}</div> <br> <input ng-model="new_selected"> <button class="btn btn-info" ng-click="add(new_selected)">Add</button> </div> <script> var app = angular.module('myApp', []); app.controller('HelloCntl', HelloCntl); function HelloCntl($scope) { $scope.friends = [ {id:1,name: 'John'}, {id:2,name: 'Mary'}, {id:3,name: 'Mike'}, {id:4,name: 'Adam'}, {id:5,name: 'Julie'} ]; $scope.selected = $scope.friends[0]; // initialise selection $scope.delete = function(x) { var y = $scope.friends.indexOf(x); $scope.friends.splice(y, 1); } var index = 6; $scope.add = function(x) { $scope.friends.push({ id: index, name: x }); index++; $scope.new_selected = ''; } } </script> </body> </html>
您可以在第一个选择标记中添加“多个”属性。
<select ng-model="selectname1" multiple
ng-options="item as item.name for item in friends|filter:filter2|filter:filter3" ><option value="">- select -</option></select>
<div>{{selectname1}}</div>
如果我正确理解你的问题,至少这在js小提琴中起作用。
在这里你可以找到,如何将多个选择限制为三个答案: HTML Multiselect Limit
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