[英]Updating table column based on other table column
我想更新表cases_proceedings,但是它将在其他表cases_attach_files中检查一些标准,即
SELECT cp.sno FROM cases_proceedings cp, cases_attach_files cf
WHERE cp.`case_sno` = cf.`case_sno` AND cf.page_lbl_sno = 10 AND
cp.`is_decided` = 0
但是,当我想更新第一个表的值并通过对子查询使用IN操作来搜索第一个表的sno时 ,如下所示:
UPDATE cases_proceedings
SET `is_decided` = 1
WHERE sno IN(SELECT cp.sno FROM cases_proceedings cp, cases_attach_files cf
WHERE cp.`case_sno` = cf.`case_sno` AND cf.page_lbl_sno = 10 AND
cp.`is_decided` = 0);
它显示一个错误:
Error Code: 1093
You can't specify target table 'cases_proceedings' for update in FROM clause
我不知道该如何解决?
一种解决方法是将子查询包装在另一个子查询中:
UPDATE cases_proceedings
SET is_decided = 1
WHERE sno IN
(
SELECT sno
FROM
(
SELECT cp.sno
FROM cases_proceedings cp
INNER JOIN cases_attach_files cf
ON cp.case_sno = cf.case_sno AND
cf.page_lbl_sno = 10 AND
cp.is_decided = 0
) t
);
额外的子查询可解决该错误,因为它迫使MySQL实现包含联接的子查询。
根据文档 ,在MySQL中,您不能修改在SELECT部分中使用的同一表。
您可以将其包装在子查询中,也可以将两个表连接起来,如下所示:
UPDATE cases_proceedings cp
INNER JOIN cases_attach_files cf
ON cp.case_sno = cf.case_sno
AND cf.page_lbl_sno = 10
AND cp.is_decided = 0
SET cp.is_decided = 1
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