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[英]How to make a hyperlink to all the rows in a particular column of a table using php
[英]How to Traverse all rows in a column using php
这是我的表数据和行
users under_userid
------- ------------
demo NULL
user1 demo
user2 user1
user3 user1
user4 user2
我试过如下查询
$query = mysqli_query($con,"select under_userid from user where users='user4'");
$result = mysqli_fetch_array($query);
foreach ($result as $x => $x_value)
{
echo 'Value = ' . $x_value;
}
我得到了上述语句的输出
Value = user2
但我需要从输出值中获取所有 under_userid
Expected Output
Value = user2
Value = user1
Value = demo
如何从输出值中获取所有 under_userid?
那么我需要使用 PHP 正确的 MySQL 查询和循环语句吗?
你需要一个递归函数:
function get_all_under($con, $userid) {
$stmt = mysqli_prepare($con, "SELECT under_userid FROM user where user = ? AND under_userid IS NOT NULL");
mysqli_stmt_bind_param($stmt, "s", $userid);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $under_userid);
$results = array();
while (mysqli_stmt_fetch($stmt)) {
echo "Value = $under_userid<br>";
$results[] = $under_userid;
}
// Now get the next level
foreach ($results as $under_userid) {
get_all_under($con, $user_userid);
}
}
get_all_under("user4");
将您的查询替换为:
SELECT under_userid FROM user WHERE under_userid != 'NULL'
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