PHP MySQL UPDATE 语句
[英]PHP MySQL UPDATE statement
问题描述
我正在制作一个网站，在您登录并在数据库中添加所有联系人后，您还可以编辑它们。 要走的路是 MYSQL UPDATE 语句。 我已经编写了代码，但有些东西似乎不起作用，并且已经折磨了我几个小时。 这是代码
<?php
session_start();
$del_id = $_GET["id"];
$_SESSION["id"] = $del_id;
$del_name = $_GET["name"];
$del_phone = $_GET["phone"];
$del_address = $_GET["address"];
$del_email = $_GET["email"];
$name2 = $_POST["name"];
$address2 = $_POST["address"];
$number2 = $_POST["number"];
$email2 = $_POST["email"];
$query = "UPDATE `contacts` SET email = '$email2' AND phone = '$number2' AND address = '$address2' AND name = '$name2' WHERE id = '$del_id'";
$conn = mysqli_connect($servername,$username,$password,$dbname);
if(!$conn){
die("Connection failed: ".mysqli_connect_error());
}else{
echo "Connected successfully";
}
if(mysqli_query($conn,$query)){
echo "Contact edited";
}
?>
<html><head></head>
<body>
<form action="edit.php" method = "POST">
Add text only to the ones you want changed:<br><br>
NAME<input type="text" value="<?php echo $del_name?>" name="name"><br>
ADDRESS<input type="text" value="<?php echo $del_address?>" name="address"><br>
PHONE NUMBER <input type="text" value="<?php echo $del_phone ?>" name="number"><br>
EMAIL <input type="text" value="<?php echo $del_email ?>" name="email"><br>
<input type="submit" value="Submit">
</form>
</body>
</html>
之后数据库中的联系人没有更新，可能是什么问题？
3 个解决方案
解决方案1
2 2018-02-14 20:42:57
您的 UPDATE 语句是错误的：
"UPDATE `contacts` SET email = '$email2' AND phone = '$number2' AND address = '$address2' AND name = '$name2' WHERE id = '$del_id'"
试试这个
// Please sanitize the data
$email2 = filter_var( $email2, FILTER_SANITIZE_EMAIL );
$name2 = preg_replace( "#[^a-zA-Z ]#", '', $name2 );
$number2 = preg_replace( "#[^0-9 \-\+]#", '', $number2 );
$address = preg_replace( "[^\w \.\-\+]#", '', $address2 );
"UPDATE `contacts` SET email = '$email2', phone = '$number2', address = '$address2', name = '$name2' WHERE id = '$del_id' LIMIT 1"
笔记
我添加了限制子句LIMIT 1来限制将受更新语句影响的行数。 在这种情况下，我将其设置为1以确保我们正在更新单行。 我相信你也会想要的。
* 请考虑使用 mysqli 准备好的查询或 PDO
解决方案2
-1 2018-02-14 20:42:37
替换您的$query行。
$query = "UPDATE `contacts`
SET email = '$email2', phone = '$number2', address = '$address2', name = '$name2'
WHERE id = '$del_id'";
AND可以用在WHERE子句中。
解决方案3
-3 2018-02-14 20:43:15
$query = "UPDATE `users` SET `userpassword` = CONCAT(`userpassword`, 'a') WHERE `user_id` = 1";
阅读指南
PHP中的MySQL更新语句
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