Javascript RegEx在斜杠和逗号或问号之间的url中查找字符串

Question

我想从以下网址获取javascript返回值“ sct”或“ rain”（将“，20”或“，70”剥离）：

<script>
var urls = [
"https://api.weather.gov/icons/land/day/sct,20?size=medium",
"https://api.weather.gov/icons/land/day/sct?size=medium",
"https://api.weather.gov/icons/land/night/rain?size=medium",
"https://api.weather.gov/icons/land/day/rain,60/rain,70?size=medium"
];
for(var key in urls) {
  console.log(get_icon(urls[key]));
}
function get_icon(text) {
 /* not sure what to do here */
}
</script>

逻辑将在最后一个斜杠之后，逗号或问号之前得到字符串。 我正在用正则表达式声明来做到这一点。

Answer 1

您可以将此正则表达式与.*的贪婪匹配一起使用，以确保last /被匹配：

/.*\/([^,?]+)/

正则演示

([^,?]+)给您下一个字符串? 或,在捕获组中。

码：

 var urls = [ "https://api.weather.gov/icons/land/day/sct,20?size=medium", "https://api.weather.gov/icons/land/day/sct?size=medium", "https://api.weather.gov/icons/land/night/rain?size=medium", "https://api.weather.gov/icons/land/day/rain,60/rain,70?size=medium" ]; for(var key in urls) { console.log(get_icon(urls[key])); } function get_icon(text) { return (text.match(/.*\\/([^,?]+)/) || [null][null])[1]; } 

Answer 2

请检查此正则表达式。 提取组1：

\S+\/(\w+,\d+|\w+)\?\w+=\w+

Answer 3

回复您的需要，我可以做：

function get_icon(text) {
   var pos = text.lastIndexOf("/");
   var qmark = text.lastIndexOf("?size");
   var res = text.substring(pos+1, qmark);
   var res = res.split(",");
   if (res.length == 2)
      return res[1];
   else
      return null;
}