如何检查数组是否包含对象的值

Question

可以说我们有一个像这样的对象：

{"A":["00002","00003","00004"]}

和一个数组：

["00002", "00003"]

我想做的是检查Objects值，如果键值不在数组中全部存在，则提醒用户键A值在数组中不存在。

如果A未知，该怎么办？

Answer 1

您可以在数组上执行.filter并检查所有值是否在另一个数组中。

 var obj = {"A":["00002","00003","00004"]} var check = ["00002", "00003"]; if(obj.A.filter(el => !check.includes(el)).length){ console.log("Some elements does not exists"); } 

更新：如果您不知道关键是什么：

可能有多种方式，我将使用Object.values(obj)[0]来访问数组。

 var obj = {"A":["00002","00003","00004"]} var check = ["00002", "00003"]; if(Object.values(obj)[0].filter(el => !check.includes(el)).length){ console.log("Some elements does not exists"); } 

Answer 2

您应该在对象内部检索数组：

object.A

接下来，您需要遍历要检查的数组

var allMatch = true;
var object = {"A":["00002","00003","00004"]};
["00002", "00003"].forEach(function(item){
    if(object.A.indexOf(item) === -1){ // -1 when not found
        allMatch = false;
    }
});

alert("Do they all match? " + allMatch);

或者，如果您需要旧版Internet Explorer支持。

var allMatch = true;
var object = {"A":["00002","00003","00004"]};
var arr = ["00002", "00003"];
for(var i=0;i<arr.length;i++){
    if(object.A.indexOf(arr[i]) === -1){ // -1 when not found
        allMatch = false;
        break; // Stop for loop, since it is false anyway
    }
};

alert("Do they all match? " + allMatch);

Answer 3

只是循环并检查。

 var haystack = {"A":["00002","00003","00004"]}; var needle = ["00002", "00003"]; function allItemsExist(h, n){ for(var k in h) if(!~n.indexOf(h[k])) return false; return true; } if(!allItemsExist(haystack.A, needle)) alert("something is missing"); else alert("everything is here"); 

Answer 4

function containsAllData(obj, key, arr)
{
   if(arr.length < obj[key].length)
   {
      alert("Array is not fully contained!");
      return false;
   }
   for(var i = 0; i < obj[key].length; i++)
      if(arr[i] !== obj[key][i])
      {   
         alert("Array contains different data!");
         return false;
      }
   return true;
}