HIVE在多个表中分组

Question

两张表-'salaries'和'master1'

薪水是按年计算的，我可以将其分组以使用

SELECT playerID, sum(salary) as sal 
FROM salaries 
GROUP BY playerID ORDER BY sal DESC LIMIT 10; 

这将返回玩家ID和薪水总和，但我需要“ master1”表“ nameFirst”和“ nameLast”列下的玩家名称。 它们在“ master1”和“ salaries”中都有“ playerID”的公共列，但是当我尝试运行时

SELECT master1.nameFirst, master1.nameLast, sum(salary) as sal 
FROM salaries, master1 
GROUP BY salaries.playerID ORDER BY sal DESC LIMIT 10; 

我收到错误表达式不在GROUP BY键'nameFirst'中的信息

我尝试修改它，以继续得到错误。

谢谢！

Answer 1

需要包括nameFirst和nameLast将在group by ：

SELECT 
master1.nameFirst, 
master1.nameLast, 
sum(salary) as sal 
FROM salaries JOIN master1 ON salaries.playID = master1.playerID
GROUP BY master1.nameFirst, master1.nameLast, salaries.playerID 
ORDER BY sal DESC LIMIT 10;

Answer 2

首先，您需要使用正确的显式JOIN语法

SELECT  
        MAX(m.nameFirst) FirstName,
        MAX(m.nameLast) LastName,
        SUM(s.salary) Salary
FROM master1 m
INNER JOIN salaries s ON m.playerID = s.playerID 
GROUP BY m.playerID 

使用master1表获取FirstName ， LastName并使用salaries表进行JOIN以获取每个玩家的总薪水。

因此，当您使用GROUP BY子句时，当前查询异常应确保SELECT语句中的列/表达式需要聚合。