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剩下两个表连接一个,而不是从连接中获取所有数据

[英]two tables left join the one, not getting all the data from the join

我有一张表,如下所示:

tickets:
id       integer primary key
home_org varchar

有一个homeorgs表,其中包含所有家庭组织,并包括如下的部门代码:

homeorgs:
home_org      varchar
division_code varchar

我希望能够显示每个部门每个月的门票数量,即使某个特定部门没有提交任何门票。 对于没有票证的部门,我需要显示0(零)。

这是SQL:

select 
       count(t.id) as ticket_count,
       to_number(to_char(t.submitdate,'MM'), '99') as mon,
       to_number(to_char(t.submitdate,'YYYY'), '9999') as yr,
       nd.division_key 
  from homeorgs as h 
       LEFT JOIN tickets as t
           ON t.home_org = h.home_org 
           and t.submitdate >= '2018-02-01 00:00:00'
           and t.submitdate <= '2018-02-28 23:59:59'
  where t.home_org is not null
 group by h.division_key, mon, yr
 order by yr, mon, h.division_key 

此sql不会引入没有提交票证的homeorg行。

我在这里做错了什么?

只需删除“ t.home_org不为空”,这可以防止票证表中的记录不匹配。

  select 
       count(t.id) as ticket_count,
       to_number(to_char(t.submitdate,'MM'), '99') as mon,
       to_number(to_char(t.submitdate,'YYYY'), '9999') as yr,
       nd.division_key 
  from homeorgs as h 
       LEFT JOIN tickets as t
           ON t.home_org = h.home_org 
           and t.submitdate >= '2018-02-01 00:00:00'
           and t.submitdate <= '2018-02-28 23:59:59'
 group by h.division_key, mon, yr
 order by yr, mon, h.division_key

您的问题可能只是where子句。 这是为查询的其他部分建议更简单的逻辑:

select count(t.id) as ticket_count,
       extract(month from t.submitdate) as mon,
       extract(year from t.submitdate) as yr,
       h.division_key 
from homeorgs h left join
     tickets as t
    on t.home_org = h.home_org and
       t.submitdate >= '2018-02-01' and
       t.submitdate < '2018-03-01'
group by h.division_key, mon, yr
order by yr, mon, h.division_key ;

就个人而言,我不会将年和月分成不同的列。 我只是将日期截断到月初:

select count(t.id) as ticket_count, date_trunc('month', t.submitdate) as yyyymm,
       h.division_key 
from homeorgs h left join
     tickets as t
    on t.home_org = h.home_org and
       t.submitdate >= '2018-02-01' and
       t.submitdate < '2018-03-01'
group by h.division_key, yyyymm
order by yyyymm, h.division_key ;

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