[英]MS Access parameterized passthrough query
我在获取带有参数的查询以在要构建的MS Access DB中工作时遇到了一个小问题。 参数为数字形式时,我无法正确设置格式/语法。
这是代码:
Private Sub Command15_Click()
Dim conn As ADODB.Connection
Dim strConnection As String
strConnection = "Driver={Microsoft ODBC for Oracle};Server=SERVER;Uid=USER_ID;Pwd=PASSWORD;"
Set conn = New ADODB.Connection
conn.Open strConnection
conn.Execute " UPDATE L2000.DEPARTURE_STATUS DS " & _
" SET DS.DEPARTURE_STATUS = '" & Forms!frmDepartureStatus.txtdeparturestatus & "' " & _
" WHERE DS.DEPARTURE_NO = " & Forms!frmDepartureStatus.txtdepno
conn.Close
Set conn = Nothing
End Sub
通过参数从txtdepno发送的值是一个数字,我尝试了几种不走运的方法。
这是另一个类似的代码,但是这次参数是一个字符串:
Private Sub Command16_Click()
Dim conn As ADODB.Connection
Dim strConnection As String
strConnection = "Driver={Microsoft ODBC for Oracle};Server=SERVER;Uid=USER_ID;Pwd=PASSWORD;"
Set conn = New ADODB.Connection
conn.Open strConnection
conn.Execute " UPDATE L2000.USERS U " & _
" SET U.STORER_ID = '" & Forms!EXAMPLE.txtInput2 & "'" & _
" WHERE U.USER_ID = '" & Forms!EXAMPLE.txtInput & "'"
conn.Close
Set conn = Nothing
End Sub
字符串串联不是参数化。 但是,如果您使用字符串连接,则可以很轻松地解决此问题。 只需省略单引号,这样Oracle会将其视为数字。 用单引号将它们视为字符串:
Private Sub Command16_Click()
Dim conn As ADODB.Connection
Dim strConnection As String
strConnection = "Driver={Microsoft ODBC for Oracle};Server=SERVER;Uid=USER_ID;Pwd=PASSWORD;"
Set conn = New ADODB.Connection
conn.Open strConnection
conn.Execute " UPDATE L2000.USERS U " & _
" SET U.STORER_ID = " & Forms!EXAMPLE.txtInput2 & _
" WHERE U.USER_ID = " & Forms!EXAMPLE.txtInput
conn.Close
Set conn = Nothing
End Sub
如果您确实想构建一个参数化查询,它将看起来像这样:
Private Sub Command16_Click()
Dim conn As ADODB.Connection
Dim strConnection As String
strConnection = "Driver={Microsoft ODBC for Oracle};Server=SERVER;Uid=USER_ID;Pwd=PASSWORD;"
Set conn = New ADODB.Connection
conn.Open strConnection
Dim cmd As New ADODB.Command
Set cmd.ActiveConnection = conn
cmd.CommandText = "UPDATE L2000.USERS U " & _
" SET U.STORER_ID = ?"
" WHERE U.USER_ID = ?"
cmd.Parameters.Append cmd.CreateParameter(, adInteger,adParamInput, 5, Forms!EXAMPLE.txtInput2 )
cmd.Parameters.Append cmd.CreateParameter(, adInteger,adParamInput, 5, Forms!EXAMPLE.txtInput )
cmd.Execute
conn.Close
Set conn = Nothing
End Sub
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