PHP | 如何发布请求正文？

Question

如何在下一个查询中发布请求？

请求正文：

_username=test%40test.com&_password=1234&_remember_me=true

PHP：

$opts = array('http'=>
array(
'proxy'=>"",
'method'=>"POST",
'header'=>"User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:51.0) Gecko/20100101 Firefox/51.0"
));

$context  = stream_context_create($opts);
$result = file_get_contents('https://website.com/login_check', false, $context);

Answer 1

有关更多详细信息，请检查文档

$opts = array(
    'http'=>
        array(
          'proxy' => "",
          'method' => "POST",
          'content' => '_username=test%40test.com&_password=1234&_remember_me=true',
          'header' => "User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:51.0) Gecko/20100101 Firefox/51.0"
        )
);

$context  = stream_context_create($opts);
$result = file_get_contents('https://website.com/login_check', false, $context);

还要检查如何使用file_get_contents在PHP中发布数据？