在C＃中使用CsvHelper写入CSV文件

Question

我试图在C＃中使用CsvHelper写入CSV文件。 这是库http://joshclose.github.io/CsvHelper/的链接。没有任何内容发送到csv文件。 我尝试做“ exportCsv.WriteField("Hello"); “，但仍然没有任何反应。

List<string> ColumnOne = new List<string>();
List<string> ColumnTwo = new List<string>();
var csvTextWriter = new 
    StreamWriter(@"C:\Users\Public\Documents\ExportTest.csv");
var exportCsv = new CsvWriter(csvTextWriter);
    //creating a list to store workflows then adding name and description to the myWorkflowsList list
   if (myWorkflows.WorkFlowCollection.Any())
   {
        foreach (var Workflow in myWorkflows.WorkFlowCollection)
        {
                    ColumnOne.Add(Workflow.WorkflowName);
                    ColumnTwo.Add(Workflow.WorkflowDescription);
        }
        exportCsv.WriteField(ColumnOne);
        //exportCsv.WriteField(ColumnTwo);
        exportCsv.NextRecord();
        exportCsv.Flush();
        Console.WriteLine("File is saved: 
                C:\\Users\\Public\\Documents\\ExportTest.csv");
        Console.ReadLine();
    }

Answer 1

您的代码没有添加任何记录。 它没有对WriteRecords或WriteRecord任何调用。 看起来它正在尝试将整个字符串列表写入单个字段中。

要将两列写到文件中，可以使用`WriteRecords，例如：

var data = from flow in myWorkflows.WorkFlowCollection
           select new { flow.WorkflowName,flow.WorkflowDescription};
using (var writer = new StreamWriter("test.csv"))
using (var csv = new CsvWriter(writer))
{
    csv.WriteRecords(data);
}

这将写入一个字段名称为WorkflowName和WorkflowDescription的文件

您可以通过创建一个仅接受所需字段并通过属性设置名称等的小类来更改字段的编写方式：

class Flow
{

    [NameAttribute("Workflow Name")]
    public string WorkflowName { get; set; }
    [NameAttribute("Workflow Description")]
    public string WorkflowDescription { get; set; }

    public Flow(string workflowName, string workflowDescription)
    {
        WorkflowName = workflowName;
        WorkflowDescription = workflowDescription;
    }
}


//...
var data = from flow in myWorkflows.WorkFlowCollection
           select new Flow(flow.WorkflowName,flow.WorkflowDescription);
using (var writer = new StreamWriter("test.csv"))
using (var csv = new CsvWriter(writer))
{
    csv.WriteRecords(data);
}