[英]Select Max(Field) not working
我有以下问题:
SELECT MAX(SEQUENCE) FROM TABLE1
WHERE FIELD99= 'NUMBER'
该查询带来了Field1的MAX值,并且运行良好。 现在,我想将此信息与另一个表结合起来以收集其他数据,并且我正在使用它:
SELECT MAX(B.SEQUENCE), A.COUNTRY, A.COMPANY,
A.DOCNUMBER, B.USERID, B.REASON
FROM TABLE1 A
INNER JOIN TABLE2 B
ON A.DOCNUMBER=B.DOCNUMBER
WHERE A.DOCNUMBER='NUMBER'
GROUP BY B.SEQUENCE, A.COUNTRY, A.COMPANY, A.DOCNUMBER, B.USERID, B.REASON
我知道问题出在分组,但是我不知道,我尝试了几种方法,但是我注意到,当我删除所有其他字段时,它只会带来我想要的数据。
如果运行给出的第一个示例,将得到结果:007,这是字段SEQUENCE的最大值。 如果我运行另一个查询,我将得到:
001 + all the other fields
002 + all the other fields
003 + all the other fields
004 + all the other fields
005 + all the other fields
006 + all the other fields
007 + all the other fields
我希望结果将与第一个查询相同的行带入选择中添加的数据
我能够执行此查询并解决问题
SELECT DISTINCT A.REFFSEQU, A.CTRYCODE, A.COMPCODE, A.INVONUMB, A.REFFERRS, A.REFFERBY
FROM TABLE1 A, TABLE2 B
WHERE A.CTRYCODE=B.CTRYCODE AND A.COMPCODE=B.COMPCODE AND A.INVONUMB=B.INVONUMB
AND B.INVOCRDT > '20180101'
AND (A.REFFSEQU = ANY
(SELECT MAX(REFFSEQU)
FROM TABLE1 AS D
WHERE D.CTRYCODE=A.CTRYCODE AND D.COMPCODE=A.COMPCODE
AND D.INVONUMB= A.INVONUMB))
AND A.REFFERRS = 'DUPLICATION, RECORD REJEC'
这就是结果,对不起如何在这里做表格
REFFSEQU CTRYCODE COMPCODE INVONUMB REFFERRS REFFERBY
001 631 01 number1 DUPLICATION, RECORD REJEC id
002 631 01 number2 DUPLICATION, RECORD REJEC id
002 631 01 number3 DUPLICATION, RECORD REJEC id
007 631 01 number4 DUPLICATION, RECORD REJEC id
007 631 01 number5 DUPLICATION, RECORD REJEC id
我会使用CTE来做到这一点。 它将简化分组。
with tmp as (
select docnumber,
max(sequence) as sequence,
country,
company
from table1
group by docnumber)
select a.sequence, a.country, a.company, a.docnumber, b.userid, b.reason
from tmp a
join table2 b on a.docnumber = b.docnumber
where a.docnumber = 'NUMBER'
注意,我使用的是table1
而不是table2
序列。
编辑:这是基于评论的初步猜测:
with tmp as (
select docnumber, max(sequence) as sequence
from table1
group by docnumber),
tmp2 as (
select distinct docnumber
from table2
where reason = 'Duplicated')
select a.sequence, a.country, a.company, a.docnumber, b.userid, b.reason
from tmp a
join table2 b on a.docnumber = b.docnumber
join tmp2 c on a.docnumber = c.docnumber
where a.docnumber = 'NUMBER'
如果每个文档编号的序列不超过一个,且原因为“重复”,则不需要tmp2
定义中的非重复。
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