如何使用Codeigniter在数据库中存储多个复选框值

Question

<tr><th>Option Subject</th>
 <th>
<input type="checkbox" name="skills" id="skills[]" value="C++"> C++<br>
<input type="checkbox" name="skills" id="skills[]" value="JAVA"> JAVA<br>
<input type="checkbox" name="skills" id="skills[]" value="HTML"> HTML<br>
<input type="checkbox" name="skills" id="skills[]" value="PHP"> PHP<br>
<input type="checkbox" name="skills" id="skills[]" value="ASP.NET">ASP.NET<br>
<font color="#FF0000"><?php echo form_error('skills');?></font>
 </th>
</tr>

控制器公共功能insert（）{$ skills = $ this-> form_validation-> set_rules（'skills'，'Option Subject'，'required'）;

$data = array(
    'skills' => implode(",", $skills);       
);
}



if(isset($options['skills'])) 
 $this->db->set('skills',($options['skills']));  
 $this->db->insert("regi_user");  
 return $this->db->insert_id();  

Answer 1

您必须将内含值转换为字符串。

试试下面的代码

 $data = array(
        'skills' => json_encode(implode(",", $skills));       
    );

    $this->db->insert("regi_user");  
    return $this->db->insert_id();  

Answer 2

要在表中添加多个值，请尝试以下代码。

$language = $this->input->post('skills');

if (is_array($language) && !empty($language))
{
    foreach($language as $lan)
    {
        $insert['language'] = $lan;
        $this->db->insert("table name");
    }
}