如何通过单击图标来更改超棒字体的颜色

Question

 var garbage = document.getElementById("garbage"); garbage.addEventListener("click",function(){ garbage.style.color = "#66c144"; } 

 <link href="https://use.fontawesome.com/releases/v5.0.10/css/all.css" rel="stylesheet"> <div id="garbage"> <i class="fas fa-trash"></i> </div> 

嗨，我正在尝试通过单击图标来更改超棒垃圾桶图标的字体颜色。 但是，它不起作用。 我将不胜感激有关如何进行这项工作的任何提示。

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 var trash = document.getElementById("trash"), glass = document.getElementById("glass"), organic = document.getElementById("organic"), plastic = document.getElementById("plastic"), paper = document.getElementById("paper"); trash.addEventListener("click",function(){ this.children[0].style.color = "#66c144"; glass.children[0].style.color = "#ffffff"; organic.children[0].style.color = "#ffffff"; plastic.children[0].style.color = "#ffffff"; paper.children[0].style.color = "#ffffff"; }); glass.addEventListener("click",function(){ this.children[0].style.color = "#66c144"; trash.children[0].style.color = "#ffffff"; organic.children[0].style.color = "#ffffff"; plastic.children[0].style.color = "#ffffff"; paper.children[0].style.color = "#ffffff"; }); organic.addEventListener("click",function(){ this.children[0].style.color = "#66c144"; trash.children[0].style.color = "#ffffff"; glass.children[0].style.color = "#ffffff"; plastic.children[0].style.color = "#ffffff"; paper.children[0].style.color = "#ffffff"; }); plastic.addEventListener("click",function(){ this.children[0].style.color = "#66c144"; trash.children[0].style.color = "#ffffff"; glass.children[0].style.color = "#ffffff"; organic.children[0].style.color = "#ffffff"; paper.children[0].style.color = "#ffffff"; }); paper.addEventListener("click",function(){ this.children[0].style.color = "#66c144"; trash.children[0].style.color = "#ffffff"; glass.children[0].style.color = "#ffffff"; organic.children[0].style.color = "#ffffff"; plastic.children[0].style.color = "#ffffff"; }); 

 <link href="https://use.fontawesome.com/releases/v5.0.10/css/all.css" rel="stylesheet"> <div class="icons flex"> <div id="trash"> <i class="fas fa-trash"></i> </div> <div id="glass"> <i class="fas fa-wine-glass"></i> </div> <div id="organic"> <i class="fab fa-envira"></i> </div> <div id="plastic"> <i class="far fa-hdd"></i> </div> <div id="paper"> <i class="far fa-newspaper"></i> </div> </div> 

更新因此，在每个人的帮助下，我设法获得了想要的结果（每次单击不同的图标，只有单击的图标具有不同的颜色）。 最重要的是，我很好奇是否存在使用“功能”之类的方法来执行我现在喜欢的重复性或混乱程度较小的方法。 如果能得到一些提示，我将不胜感激。

Answer 1

您缺少); 在结束之后} ：

 var garbage = document.getElementById("garbage"); garbage.addEventListener("click",function(){ garbage.style.color = "#66c144"; }); 

 <link href="https://use.fontawesome.com/releases/v5.0.10/css/all.css" rel="stylesheet"> <div id="garbage"> <i class="fas fa-trash"></i> </div> 

注意：您不需要定位 父 对象 ，只需将id赋予图标即可。

Answer 2

这是更改FA图标的其他一些选项。 关键字this表示garbage 。 .property或.method()/.function()引用图标。

参考

。孩子

.querySelector（）

.getElementsByTagName（）

.classList

.firstElementChild

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演示

 var garbage = document.getElementById("garbage"); garbage.addEventListener("click", function() { this.children[0].style.color = "#66c144"; this.querySelector('.fas').style.fontSize = '3rem'; this.getElementsByTagName('I')[0].classList.toggle('fa-spin'); this.firstElementChild.style.transition = 'color 1.5s ease 1.25s, font-size 0.75s ease-out'; }, false); 

 <link href="https://use.fontawesome.com/releases/v5.0.10/css/all.css" rel="stylesheet"> <div id="garbage"> <i class="fas fa-trash"></i> </div> 

Answer 3

在事件侦听器之后，您缺少右括号：

var garbage = document.getElementById("garbage");

garbage.addEventListener("click",function(){
    garbage.style.color = "#66c144";
});