[英]ajax in jsp call sql query when select dropdown value
从下拉列表中选择时,需要帮助才能从jsp的sql表中获取值。
当我选择CL时,我想在jsp中运行查询以从sql表中获取所有记录。
$(document).ready(function() { $leavetype= $('.leavetype'); $leavetype.change(function (){ var value = $('.leavetype').val(); $.ajax({ type: "post", url: "applicationformuser.jsp", //this is my servlet data: {leavetype : value}, success: function(msg){ alert(msg.data); } }); }); });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script> <select class="leavetype" name="leavetype"style="position:absolute;margin-left:160px;margin-top:160px;height:30px;width:300px;"> <option value="CL">CL</option> <option value="ML">ML</option> <option value="SL">SL</option> <option value="EL/PL">EL/PL</option> <option value="CPL">CPL</option> </select>
尝试这个
<select class="leavetype" name="leavetype" style="position:absolute;margin-left:160px;margin-top:160px;height:30px;width:300px;" onchange="GetAllDetails(this.value);">
<option value="CL">CL</option>
<option value="ML">ML</option>
<option value="SL">SL</option>
<option value="EL/PL">EL/PL</option>
<option value="CPL">CPL</option>
</select>
function GetAllDetails(value) {
$.ajax({
type: "post",
url: "applicationformuser.jsp", //this is my servlet
data: { leavetype: value },
success: function (msg) {
alert(msg.data);
}
});
}
您的ajax
代码工作正常,您只需要在jsp代码中获取它,就可以使用request.getParameter()
获取参数:
<%
String leavetype = request.getParameter("leavetype");//after get value,you can pass it to query sql.
%>
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