PHP表单提交但在重新加载表单之前不会显示错误或成功消息

Question

我有一个联系表单，其中使用PHP完成服务器端的工作。

我遇到的问题是，单击“提交”按钮时正在提交表单，但是没有显示表单，错误消息或成功消息。

当我重新加载页面时，将显示该表格和相应的消息。

我看不出有什么清楚的理由可以解释为什么会有这样的帮助！

<?php

// $error and $success variable set to blank 
$error = ""; 
$successMessage = "";

// check to see if any $_POST variables have been entered
if ($_POST) {

    // if $_POST variable ["email"] has no value
    if (!$_POST["email"]) {
        // $error variable to add comment advising that data is missing
        $error .= "An email address is required!!!!!!!!<br>";
    }

    if (!$_POST["subject"]) {
        $error .= "The subject field is required!!!!<br>";
    }

    if (!$_POST["content"]) {
        $error .= "The content field is required!!!!!<br>";
    }

    // IF $error variable is no longer empty 
    if ($error != "") {
        // $error variable to genereate html + $error 
        $error = '<div><p><strong>Whoops! There were error(s) in the form:</strong></p>' . $error . '</div>';
    } else {    
        $emailTo = "email@example.com";
        $subject = $_POST["subject"];
        $content = $_POST["content"]; 
        $headers = "From: ".$_POST["email"];
        // IF all email variables have had values assigned then $successMessage to display html sucess message
        if (mail($emailTo, $subject, $content, $headers)) {
        $successMessage = '<div>Thank you for your enquiry, we will get back to you shortly!</div>';
        // ELSE email variable(s) are missing a value - $error variable to display html error message
        } else {
        $error = '<div>Unfortuantely your enquiry could not be sent, please try again later</div>';
        }

    }

}

?>

<html>

<div id="contactOuter">
    <div id="contactInner">
            <a href="javascript:void(0);"><span id="close">&times;</span></a>
            <h1>Get in touch</h1>
            <div><? echo $error.$successMessage;?></div>
                <form method="post">
                    <label for="email">Email address:</label><br>
                    <input name="email" type="email"  placeholder="Enter email" id="email">
                    <label for="subject">Subject:</label>
                    <input name="subject" type="text" id="subject">
                    <label for="content">What would you like to ask us?</label><br>
                    <textarea name="content" rows="7" id="content"></textarea>
                    <button type="submit" id="submit">Submit</button>
                </form>
    </div>
</div>

</html>

Answer 1

编辑：给定新信息，当您单击“提交”时，表单也会消失，您很可能会收到PHP错误。 请阅读有关PHP死亡白屏的信息，并启用错误消息传递功能，以便您进行故障排除并查看可能存在的错误。 我可能还会建议您研究Xdebug或类似的其他工具，以便您逐步检查代码以了解发生了什么。

有几个问题。 首先，请始终使用<?php 。 那是根据个人经验。 某些服务器设置为不识别<? 信不信由你。

其次，基于在将表单打印到屏幕时变量没有值的事实，我认为您不会进入条件块。 尝试使用if (isset($_POST["submit"])) {代替，并执行<button type="submit" id="submit" name="submit">Submit</button> -注意：这可能不是在给出新信息的情况下，该表单甚至没有出现在表单提交中，但仍然是一种很好的做法。

如评论中所述，包括<body>标记。 另外，请确保您包括其他推荐和必需的标记（例如， <!DOCTYPE html>和<html lang="en"> ）。

还建议在表单上使用action="file.php"属性。

<?php

// $error and $success variable set to blank 
$error = ""; 
$successMessage = "";

// check to see if any $_POST variables have been entered
if (isset($_POST["submit"])) {

    // if $_POST variable ["email"] has no value
    if (!$_POST["email"]) {
        // $error variable to add comment advising that data is missing
        $error .= "An email address is required!!!!!!!!<br>";
    }

    if (!$_POST["subject"]) {
        $error .= "The subject field is required!!!!<br>";
    }

    if (!$_POST["content"]) {
        $error .= "The content field is required!!!!!<br>";
    }

    // IF $error variable is no longer empty 
    if ($error != "") {
        // $error variable to genereate html + $error 
        $error = '<div><p><strong>Whoops! There were error(s) in the form:</strong></p>' . $error . '</div>';
    } else {    
        $emailTo = "email@example.com";
        $subject = $_POST["subject"];
        $content = $_POST["content"]; 
        $headers = "From: ".$_POST["email"];
        // IF all email variables have had values assigned then $successMessage to display html sucess message
        if (mail($emailTo, $subject, $content, $headers)) {
        $successMessage = '<div>Thank you for your enquiry, we will get back to you shortly!</div>';
        // ELSE email variable(s) are missing a value - $error variable to display html error message
        } else {
        $error = '<div>Unfortuantely your enquiry could not be sent, please try again later</div>';
        }

    }

}

?>

<html>
</body>

<div id="contactOuter">
    <div id="contactInner">
            <a href="javascript:void(0);"><span id="close">&times;</span></a>
            <h1>Get in touch</h1>
            <div><?php echo $error.$successMessage;?></div>
                <form method="post">
                    <label for="email">Email address:</label><br>
                    <input name="email" type="email"  placeholder="Enter email" id="email">
                    <label for="subject">Subject:</label>
                    <input name="subject" type="text" id="subject">
                    <label for="content">What would you like to ask us?</label><br>
                    <textarea name="content" rows="7" id="content"></textarea>
                    <button type="submit" id="submit" name="submit">Submit</button>
                </form>
    </div>
</div>

</body>    
</html>

PHP表单提交但在重新加载表单之前不会显示错误或成功消息

问题描述

1 个解决方案

解决方案1
0 2018-04-24 16:49:11

PHP表单提交但在重新加载表单之前不会显示错误或成功消息

问题描述

1 个解决方案

解决方案1 0 2018-04-24 16:49:11

解决方案1
0 2018-04-24 16:49:11