繁体   English   中英

如何在多对多关联表上写查询

[英]How to write query on many to many association table

我有2个实体,并且它们之间有多对多关系。 我想在关联表上写一个查询。

Here are the two entities. Craftsmen and Skill.
I want to write a query which selects all Craftsmen with a given skill. 

    @Entity
    @Table(name = "craftsman")
    public class Craftsman {

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        private Long id;

        @ManyToMany
        @JoinTable(name = "craftman_skill", joinColumns = @JoinColumn(name = "craftman_id", referencedColumnName = "id"), 
            inverseJoinColumns = @JoinColumn(name = "skill_id", referencedColumnName = "id"))
        private List<Skill> skillList;
    }
        @Entity
        @Table(name = "skill")
        public class Skill {
            @ManyToMany(mappedBy = "skillList")
            @JsonBackReference
            private List<Craftsman> craftmanList;
        }

这是我尝试过的:

@Query("SELECT c FROM Craftsman c JOIN c.skillList sl WHERE c.skillList.skill_id = :skillId")
    public List<Craftsman> getCraftsmanBySkill(@Param("skillId") Long skillId);

这是在MySql中工作的查询:这将使所有具有ID 1技能的工匠:

select c.name from craftsman c, craftman_skill cs 
where cs.craftman_id = c.id 
and cs.skill_id = 1;

这是我得到的错误:

Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: could not resolve property: skill_id of: com.craftsmen.crafts.persistence.Skill [SELECT c FROM com.craftsmen.crafts.persistence.Craftsman c JOIN c.skillList sl WHERE c.skillList.skill_id = :skillId ]
Caused by: org.hibernate.QueryException: could not resolve property: skill_id of: com.craftsmen.crafts.persistence.Skill [SELECT c FROM com.craftsmen.crafts.persistence.Craftsman c JOIN c.skillList sl WHERE c.skillList.skill_id = :skillId ]

我想问题是,您的Skill实体确实没有skill_id或更好的id

您是否尝试给您的Skill实体提供id

@Entity
@Table(name = "skill")
public class Skill {
   @Id
   @GeneratedValue(strategy = GenerationType.IDENTITY)
   private Long id;

   @ManyToMany(mappedBy = "skillList")
   @JsonBackReference
   private List<Craftsman> craftmanList;
}

在您的Craftsman实体中引用它

@Entity
@Table(name = "craftsman")
public class Craftsman {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @ManyToMany
    @JoinTable(name = "craftman_skill", joinColumns = @JoinColumn(name = "craftman_id", referencedColumnName = "id"), 
        inverseJoinColumns = @JoinColumn(name = "skill_id", referencedColumnName = "id"))
    private List<Skill> skillList;
}

然后将Query更改为

SELECT c FROM Craftsman c JOIN c.skillList sl WHERE sl.id = :skillId

这应该够了吧。

您也可以在这里考虑使用JpaRepository的选项:

public interface CraftsmanRepository extends JpaRepository<Craftsman, String> {
    public List<Craftsman> getBySkillListIn(@NotEmpty List<Skill> skillList);

}

这意味着,Jpa通过编写方法名称已经将该查询映射到您的SQL查询(如果没有,请尝试)

并且在方法末尾,“ In”表示不应检查一个值,而应检查多个值

在SQL中, In也可以正常工作,并且可以执行以下操作:

where <condition> And <>condition And <condition> And...

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM