尚未读取对象的node.js

Question

我有和对象db_parsed

当我运行console.log(JSON.stringify(db_parsed, null, 4))

结果是：

{
    "data": [
        [
            {
                "name": "Me",
                "age": 23,
                "sex": "M"
            },
            {
                "name": "Wonderwoman",
                "age": 22,
                "sex": "F"
            }
        ],
        [
            {
                "name": "ALbert The Man",
                "age": 22,
                "sex": "M"
            }
        ],
        [
            {
                "name": "Leonard Johnson",
                "age": 23,
                "sex": "M"
            }
        ]
    ]
}

但是当我运行console.log(db_parsed.data.filter(obj => obj.age === 22))

结果是[]

为什么？ 我想念什么？ 我该如何解决？

Answer 1

db_parsed.data是一个包含arrays的数组 。

第二层数组包含对象。

您的过滤器代码试图治疗的那些对象，并直接作为内部db_parsed.data代替内部db_parsed.data[0] db_parsed.data[1]和db_parsed.data[2]

您可以使用reduce将所有第二个级别的数组连接为一个，然后对其进行过滤。

 var db_parsed = { "data": [ [{ "name": "Me", "age": 23, "sex": "M" }, { "name": "Wonderwoman", "age": 22, "sex": "F" } ], [{ "name": "ALbert The Man", "age": 22, "sex": "M" }], [{ "name": "Leonard Johnson", "age": 23, "sex": "M" }] ] }; console.log(db_parsed.data.reduce((a,b) => a.concat(b), []).filter(obj => obj.age === 22)) 

Answer 2

您可以执行[].concat.apply([], db_parsed.data)然后过滤对象数组：

 const db_parsed = {"data": [[{"name": "Me","age": 23,"sex": "M"},{"name": "Wonderwoman","age": 22,"sex": "F"}],[{"name": "ALbert The Man","age": 22,"sex": "M"}],[{"name": "Leonard Johnson","age": 23,"sex": "M"}]]}; const result = [].concat.apply([], db_parsed.data).filter(obj => obj.age === 22); console.log(result);