检查值等于数组中的特定值-javascript

Question

我有以下对象

members
    {
        [
            age:30,
            list: [
                "PRICE",
                "LIST",
                "COUNTRY"
            ]
        ]
    },
    {
        [
            age:31,
            list: [
                "PRICE"
            ]
        ]
    },
    {
        [
            age:31,
            list: [
                "LIST"
            ]
        ]
    }

我需要检查数组值是否等于特定值。

我需要检查list是否具有PRICE或list具有COUNTRY或list具有PRICE,LIST,COUNTRY组合。

目前，我正在使用includes来检查是否存在值。 但是我需要检查确切的值

Array.isArray(members.list.map(message, index){
        if(message.includes("LIST"))
        {

        }
        if(message.includes("PRICE"))
        {

        }
         if(message.includes("PRICE") && message.includes("LIST") && message.includes("COUNTRY"))
        {
            //message.includes("PRICE") and ("LIST") is already executed, so this will execute again. But i need to execute the complete condition combination.
        }
    })

如何做到这一点？

Answer 1

您的关注是遍历所有可能的if条件。
因此，您不应该在条件检查中return 。
您可以保存结果，并在匹配条件时覆盖它。 希望能帮上忙。
您的原始成员对象也存在一些问题。 在以下演示中也已修复。

 let members = [ { age: 30, list: ["PRICE", "LIST", "COUNTRY"] }, { age: 31, list: ["PRICE"] }, { age: 31, list: ["LIST"] } ]; Array.prototype.inArray = function () { var message = this; if (message.includes("PRICE") && message.includes("LIST") && message.includes("COUNTRY")) { return "contains PRICE, LIST and COUNTRY"; } if (message.includes("PRICE") && message.includes("LIST") ) { return "contains PRICE and LIST "; } if (message.includes("PRICE") && message.includes("COUNTRY")) { return "contains PRICE and COUNTRY"; } if (message.includes("LIST") && message.includes("COUNTRY")) { return "contains LIST and COUNTRY"; } if (message.includes("LIST")) { return "contains LIST"; } if (message.includes("PRICE")) { return "contains PRICE"; } if (message.includes("LIST")) { return "contains LIST"; } } for (let member of members) { console.log(member.list.inArray()); } 

Answer 2

您可以组成过滤器函数，并将其用于Array.prototype.filter

 const members = [ { age: 30, list: ["PRICE","LIST","COUNTRY"] }, { age: 31, list: ["PRICE"] }, { age: 31, list: ["LIST"] }, { age: 88, list: ["not this one"] }, { age: 88, list: ["not this one","COUNTRY","NOTPRICEORLIST"] } ] const getList = o => (o&&o.list) || [];//get list member from o or returns empty array const contains = needle => haystack => haystack.includes(needle);//check if haystack contains needle const containsAll = needles => haystack => needles.reduce( (result,needle)=>result && haystack.includes(needle), true ); const countryOrPriceOrPriceListCountry = haystack => contains("PRICE")(haystack) || contains("LIST")(haystack) //this is pointless, would already be true because it contains price or country // || containsAll(["PRICE","LIST","COUNTRY"])(haystack); const filter = getter => comparer => item =>//get something from item (list) and send to compare function comparer(getter(item)); console.log( members.filter(filter(getList)(countryOrPriceOrPriceListCountry)) ); 

或者，也许您正在寻找以下内容：

 const members = [ { age: 30, list: ["PRICE","LIST","COUNTRY"] }, { age: 31, list: ["PRICE"] }, { age: 32, list: ["LIST"] }, { age: 88, list: ["not this one"] }, { age: 89, list: ["not this one","COUNTRY","NOTPRICEORLIST"] } ] const getList = o => (o&&o.list) || [];//get list member from o or returns empty array const contains = needle => haystack => haystack.includes(needle);//check if haystack contains needle const containsAll = needles => haystack => needles.reduce( (result,needle)=>result && haystack.includes(needle), true ); const countryOrPrice = haystack => contains("PRICE")(haystack) || contains("LIST")(haystack) const countryListAndPrice = containsAll(["PRICE","LIST","COUNTRY"]); members.map( item=>[item,countryOrPrice(getList(item))]//see if item has country or price ).map( ([item,hasCountryOrPrice])=>[ item, hasCountryOrPrice, // will check for country list and price only if has country or price hasCountryOrPrice && countryListAndPrice(getList(item)) ] ).forEach( ([item,hasCountryOrPrice,countryListAndPrice])=> console.log( "item age:", item.age, "has country or price:", hasCountryOrPrice, "has country list and price:", countryListAndPrice ) ); 

Answer 3

希望这会有所帮助

 var members = [ { age: 30, list: ["PRICE", "LIST", "COUNTRY"] }, { age: 31, list: ["PRICE"] }, { age: 31, list: ["LIST"] } ]; members.forEach((val,key)=>{ if(Array.isArray(val.list)){ if(val.list.indexOf('PRICE') > -1 || val.list.indexOf('COUNTRY') > -1 || (val.list.indexOf('PRICE') > -1 && val.list.indexOf('COUNTRY') > -1 && val.list.indexOf('LIST') > -1)){ console.log(val) } } });