按升序和降序对多个数组键进行排序，带数字的字符串

Question

我有一个JavaScript对象数组：

这不是重复的问题。 因为，我有一个具有2个键（ key ， count ）的对象数组。 我想排序， key升序（ 字符串 ）和value降序（ 数字 ）。

 var array = [
  {"count":7,"key":"a"},
  {"count":10,"key":"b"},
  {"count":5,"key":"c"},
  {"count":10,"key":"a"},
  {"count":3,"key":"d"}
];

所需输出：

     var array = [
      {"count":10,"key":"a"},
      {"count":10,"key":"b"},
      {"count":7,"key":"a"},
      {"count":5,"key":"c"},
      {"count":3,"key":"d"}
    ];

 var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}]; console.log(array.sort((a, b) => (b.count - a.count))); 

key 升序排列

count为降序

我已经使用array.sort((a, b) => (b.count - a.count))方法来对计数进行排序。 但是，无法弄清楚如何对两个键进行排序。

Answer 1

您必须使用逻辑|| 运算符与localeCompare函数结合使用。

|| 如果b.count - a.count结果为零，则运算符仅考虑第二个分量。

 var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}]; console.log(array.sort((a, b) => b.count - a.count || a.key.localeCompare(b.key))); 

Answer 2

尝试跟随

 var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}]; console.log(array.sort((a, b) => { if(a.count === b.count) return a.key.localeCompare(b.key); return b.count - a.count; }));