[英]Removing duplicates from query
我在下面的查询中获取设备全天运行的百分比时间,但是由于数据中存在重复项,因此我无法轻易摆脱,这是最好的方法?
我试过使用distinct和Max(dtReading)
SELECT DISTINCT
workStationNo,
controllerID,
CAST(DATEPART(DAY, DATEADD(DAY, DATEDIFF(DAY, 0, MAX(dtReading)), 0)) AS varchar) AS date,
(CAST(COUNT(*) AS float(1)) / CAST((DATEPART(HOUR, GETDATE()) * 30) AS float(1)) * CAST(100 AS float(1))) AS dayPercentage
FROM Controller
INNER JOIN ManufacturingLayout
ON Controller.machID = ManufacturingLayout.workStationID
INNER JOIN ReaderData
ON Controller.ctrlID = ReaderData.controllerID
WHERE dtReading >= CONVERT(datetime, '09/05/2018', 103)
AND dtReading <= DATEADD(HOUR, 24, CONVERT(datetime, '16/05/2018 23:59:59', 103))
AND (EventType = '(0x05)Open switch')
GROUP BY controllerID,
DATEADD(DAY, DATEDIFF(DAY, 0, dtReading), 0),
workStationNo
ORDER BY 1, 2
查询输出
Workstation no controllerID date dayPercentage
ZW01006 38 15 80.20833
ZW01006 38 16 142.0833
ZW01007 30 15 62.5
ZW01007 30 16 120.2083
ZW01008 31 15 92.70833
ZW01008 31 16 141.0417
ZW01010 40 15 0.625
源数据
workStationNo controllerID dtReading
ZW01007 30 2018-05-16 15:42:39.000
ZW01007 30 2018-05-16 15:42:38.000
ZW01007 30 2018-05-16 15:40:38.000 <- duplicate
ZW01007 30 2018-05-16 15:40:38.000 <- duplicate
ZW01007 30 2018-05-16 15:38:37.000
ZW01007 30 2018-05-16 15:38:37.000
ZW01007 30 2018-05-16 15:36:37.000
ZW01007 30 2018-05-16 15:36:37.000
ZW01007 30 2018-05-16 15:34:36.000
您可以将派生表用于JOIN
到ReaderData
,以便在JOIN
之前删除重复项:
...
INNER JOIN (SELECT DISTINCT controllerID, dtReading
FROM ReaderData) ReaderData
...
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