[英]recursive CTE or ROW_NUMBER over partition?
您好,下面是一个小示例,我试图找到一种方法,通过CDO_OP_REFERRAL_UNIQUE_ID根据ATTENDED_OR_DID_NOT_ATTEND重置COUNT,最后一列是我每次都对保留的分区使用ROW_NUMBER时似乎无法在查询中应用的预期结果得到错误的结果是,每次ATTENDED_OR_DID_NOT_ATTEND更改时它都不会重新启动
DECLARE @CDO_OP_APPOINTMENT TABLE (CDO_OP_REFERRAL_UNIQUE_ID int,LOCAL_PATIENT_NUMBER varchar(10),APPOINTMENT_START_DATE_TIME datetime,ATTENDED_OR_DID_NOT_ATTEND varchar(10),DESIRED_OUTCOME varchar(10))
INSERT INTO @CDO_OP_APPOINTMENT
VALUES
('480805568', 'HEY1030785', '05/11/2013 10:00', '2', '1'),
('480805568', 'HEY1030785', '12/11/2013 10:00', '5', '1'),
('480805568', 'HEY1030785', '22/11/2013 09:30', '5', '2'),
('480805568', 'HEY1030785', '03/12/2013 13:00', '3', '1'),
('480805568', 'HEY1030785', '30/12/2013 10:15', '5', '1'),
('480805568', 'HEY1030785', '24/02/2014 09:15', '4', '1'),
('480805568', 'HEY1030785', '24/02/2014 14:15', '5', '1'),
('480805568', 'HEY1030785', '17/03/2014 15:25', '4', '1'),
('480805568', 'HEY1030785', '20/03/2014 18:50', '5', '1'),
('480805568', 'HEY1030785', '23/09/2014 15:55', '5', '2'),
('480805568', 'HEY1030785', '14/04/2015 16:30', '5', '3'),
('480805568', 'HEY1030785', '14/04/2015 17:30', '4', '1'),
('480805568', 'HEY1030785', '15/05/2015 14:15', '5', '1')
SELECT * from @CDO_OP_APPOINTMENT
这是一个孤岛问题。 最简单的解决方案是行号的不同:
select a.*,
row_number() over (partition by CDO_OP_REFERRAL_UNIQUE_ID, ATTENDED_OR_DID_NOT_ATTEND , seqnum - seqnum_2 order by APPOINTMENT_START_DATE_TIME) as desired_result
from (select a.*,
row_number() over (partition by CDO_OP_REFERRAL_UNIQUE_ID order by APPOINTMENT_START_DATE_TIME) as seqnum,
row_number() over (partition by CDO_OP_REFERRAL_UNIQUE_ID, ATTENDED_OR_DID_NOT_ATTEND order by APPOINTMENT_START_DATE_TIME) as seqnum_2,
from @CDO_OP_APPOINTMENT a
) a;
设法解决与上述答案非常相似
set dateformat dmy
go
DECLARE @CDO_OP_APPOINTMENT TABLE (CDO_OP_REFERRAL_UNIQUE_ID int,LOCAL_PATIENT_NUMBER varchar(10),APPOINTMENT_START_DATE_TIME datetime,ATTENDED_OR_DID_NOT_ATTEND varchar(10),DESIRED_OUTCOME varchar(10))
INSERT INTO @CDO_OP_APPOINTMENT
VALUES
('480805568', 'HEY1030785', '05/11/2013 10:00', '2', '1'),
('480805568', 'HEY1030785', '12/11/2013 10:00', '5', '1'),
('480805568', 'HEY1030785', '22/11/2013 09:30', '5', '2'),
('480805568', 'HEY1030785', '03/12/2013 13:00', '3', '1'),
('480805568', 'HEY1030785', '30/12/2013 10:15', '5', '1'),
('480805568', 'HEY1030785', '24/02/2014 09:15', '4', '1'),
('480805568', 'HEY1030785', '24/02/2014 14:15', '5', '1'),
('480805568', 'HEY1030785', '17/03/2014 15:25', '4', '1'),
('480805568', 'HEY1030785', '20/03/2014 18:50', '5', '1'),
('480805568', 'HEY1030785', '23/09/2014 15:55', '5', '2'),
('480805568', 'HEY1030785', '14/04/2015 16:30', '5', '3'),
('480805568', 'HEY1030785', '14/04/2015 17:30', '4', '1'),
('480805568', 'HEY1030785', '15/05/2015 14:15', '5', '1')
SELECT CDO_OP_REFERRAL_UNIQUE_ID ,LOCAL_PATIENT_NUMBER ,APPOINTMENT_START_DATE_TIME ,ATTENDED_OR_DID_NOT_ATTEND
,ROW_NUMBER() OVER (PARTITION BY CDO_OP_REFERRAL_UNIQUE_ID,Seq1-Seq2,ATTENDED_OR_DID_NOT_ATTEND ORDER BY APPOINTMENT_START_DATE_TIME) AS DESIRED_OUTCOME
FROM
(
SELECT *,ROW_NUMBER() OVER (PARTITION BY CDO_OP_REFERRAL_UNIQUE_ID ORDER BY APPOINTMENT_START_DATE_TIME) AS Seq1,
ROW_NUMBER() OVER (PARTITION BY CDO_OP_REFERRAL_UNIQUE_ID,ATTENDED_OR_DID_NOT_ATTEND ORDER BY APPOINTMENT_START_DATE_TIME) AS Seq2
from @CDO_OP_APPOINTMENT
)t
ORDER BY APPOINTMENT_START_DATE_TIME
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