[英]In Java8, when will the merge function be triggered in Collectors.toMap?
[英]Java8: Using Function::identity in Collectors.toMap(..) creates an argument mismatch error
鉴于这个简单的人POJO:
public class Person {
private String id;
private String name;
public Person(String id, String name) {
super();
this.id = id;
this.name = name;
}
public String getId() {
return id;
}
public String getName() {
return name;
}
}
我想收集一个Map<String, Person>
,其中key是Person的id
。
我试图像这样实现它:
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.function.Function;
import java.util.stream.Collectors;
public class CollectorMain {
public static void main(String[] args) {
List<Person> list = new ArrayList<>();
list.add(new Person("312", "John"));
list.add(new Person("454", "Alice"));
list.add(new Person("712", "Bob"));
Map<String, Person> map = list.stream()
.collect(
Collectors.toMap(Person::getId, Function::identity) // COMPILE ERROR
);
System.out.println(map.size());
}
}
但我得到一个编译错误:
CollectorMain.java:[14,41] no suitable method found for toMap(Person::getId,Function::identity)
method java.util.stream.Collectors.<T,K,U>toMap(java.util.function.Function<? super T,? extends K>,java.util.function.Function<? super T,? extends U>) is not applicable
(cannot infer type-variable(s) T,K,U
(argument mismatch; incompatible parameter types in method reference))
method java.util.stream.Collectors.<T,K,U>toMap(java.util.function.Function<? super T,? extends K>,java.util.function.Function<? super T,? extends U>,java.util.function.BinaryOperator<U>) is not applicable
(cannot infer type-variable(s) T,K,U
(actual and formal argument lists differ in length))
method java.util.stream.Collectors.<T,K,U,M>toMap(java.util.function.Function<? super T,? extends K>,java.util.function.Function<? super T,? extends U>,java.util.function.BinaryOperator<U>,java.util.function.Supplier<M>) is not applicable
(cannot infer type-variable(s) T,K,U,M
(actual and formal argument lists differ in length))
作为一个解决方案,我可以用这个lambda p -> p
替换Function::identity
,如下所示:
Map<String, Person> map = list.stream()
.collect(
Collectors.toMap(Person::getId, p -> p)
);
是否有可能使用Function::identity
?
您不应该使用方法参考。 你应该使用Function.identity()
。
如果使用方法引用,则基本上是尝试传递Supplier<Function<T, T>>
。
Map<String, Person> map = list.stream().collect(
Collectors.toMap(Person::getId, Function.identity())
);
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