Laravel Group 2按键收集

Question

我在一个Laravel项目上工作，但是遇到一个问题，我从数据库中得到了2件事（费用和付款），它返回了一个收集对象。 我需要按键将它们分组，这是数组：

    [items:protected] => Array
    (
        [0] => stdClass Object
            (
                [date_payment] => 2018-01-01
                [total_payment] => 19761.62
            )

    )

)

Illuminate\Support\Collection Object
(
[items:protected] => Array
    (
        [0] => stdClass Object
            (
                [date_payment] => 2018-01-29
                [total_charges] => 5184.4399862289
            )

        [1] => stdClass Object
            (
                [date_payment] => 2017-09-04
                [total_charges] => 0
            )

    )

 )

我需要这样：

Illuminate\Support\Collection Object
(
[items:protected] => Array
    (
        [0] => stdClass Object
            (
                [date_payment] => 2018-01-29
                [total_charges] => 5184.4399862289
                [total_payment] => 19761.62
            )

        [1] => stdClass Object
            (
                [date_payment] => 2017-09-04
                [total_charges] => 0
            )

    )

   )

我已经尝试了所有方法，在Google上进行了检查，在Laravel doc上进行了检查： https ://laravel.com/docs/5.4/collections#method-union我什么也没做，我尝试使用union / merge方法，但是不要做我想做的

谢谢你的帮助！

Answer 1

假设您有一个名为$payments的集合：

$payment = new StdClass;
$payment->date_payment = '2018-01-01';
$payment->total_payment = 19761.62;

$payments = collect([
    $payment
]);

还有另一个名为$expenses集合：

$expense1 = new StdClass();
$expense1->date_payment = '2018-01-29';
$expense1->total_charges = 5184.4399862289;

$expense2 = new StdClass();
$expense2->date_payment = '2017-09-04';
$expense2->total_charges = 0;

$expenses = collect([
    $expense1, $expense2
]);

要检索两个集合中具有相同键的元素，可以使用intersectByKeys ：

$payments->intersectByKeys($expenses);

这将检索与费用收集具有公共密钥的所有付款。

现在，要更新集合的值，可以使用transform函数：

$payments->transform(function ($payment, $index) use ($expenses) {
    $expense = $expenses->get($index);
    $payment->date_payment = $expense->date_payment;
    $payment->total_charges = $expense->total_charges;

    return $payment;
});

现在，如果将它们结合在一起：

$payments->intersectByKeys($expenses)->transform(function ($payment, $index) use ($expenses) {
    $expense = $expenses->get($index);
    $payment->date_payment = $expense->date_payment;
    $payment->total_charges = $expense->total_charges;

    return $payment;
});

输出量

Collection {#277 ▼
  #items: array:1 [▼
    0 => {#272 ▼
      +"date_payment": "2018-01-29"
      +"total_payment": 19761.62
      +"total_charges": 5184.4399862289
    }
  ]
}

欲获得更多信息：

• https://laravel.com/docs/5.5/collections#method-transform
• https://laravel.com/docs/5.5/collections#method-intersectbykeys