[英]Find object by property path in nested array of objects
我有这样的对象:
var obj = [
{
name: 'ob_1',
childFields: [],
},
{
name: 'ob_2',
childFields: [
{
name: 'ob_2_1',
childFields: [
{
name: 'ob_3_1',
childFields: [],
test: 124
},
],
},
],
},
]
function getObjectByNamePath(path, fieds) {
const pathArr = path.split('.');
const result = fieds.find(field => {
if (pathArr.length > 1) {
if (field.name === pathArr[0] && field.childFields.length) {
const newPath = pathArr.slice(1, pathArr.length).join('.');
return getObjectByNamePath(newPath, field.childFields);
}
return false;
} else {
if (field.name === pathArr[0]) {
return true;
} else {
return false;
}
}
});
return result;
}
我想通过名称值路径获取对象:
console.log(getObjectByNamePath('ob_2.ob_2_1.ob_3_1', obj))
我尝试过这个 ,但它不正确,我觉得有更优雅的方式来实现我想要的。 谢谢。
您可以迭代childFields
并找到此级别的name
,然后使用下一级别名称。
function getObjectByNamePath(path, array) { return path .split('.') .reduce( ({ childFields = [] } = {}, name) => childFields.find(o => o.name === name), { childFields: array } ); } var obj = [{ name: 'ob_1', childFields: [], }, { name: 'ob_2', childFields: [ { name: 'ob_2_1', childFields: [ { name: 'ob_3_1', childFields: [], test: 124 }] }] }]; console.log(getObjectByNamePath('ob_2.ob_2_1.ob_3_1', obj)); console.log(getObjectByNamePath('ob_1', obj)); console.log(getObjectByNamePath('foo.bar', obj));
.as-console-wrapper { max-height: 100% !important; top: 0; }
递归解决方案。
var obj = [{ name: 'ob_1', childFields: [], }, { name: 'ob_2', childFields: [ { name: 'ob_2_1', childFields: [ { name: 'ob_3_1', childFields: [], test: 124 }] }] }] function getObjectByNamePath(path, obj) { const [currentPath, ...restPaths] = path.split('.'); const nextObj = (obj.find(e => e.name === currentPath)) if(!restPaths.length) return nextObj; return getObjectByNamePath(restPaths.join('.'), nextObj.childFields || []); } // Test Cases console.log(getObjectByNamePath('ob_2.ob_2_1.ob_3_1', obj)) console.log(getObjectByNamePath('ob_2.ob_2_1.ob_3_1.fakePath', obj)) console.log(getObjectByNamePath('ob_1', obj)) console.log(getObjectByNamePath('', obj))
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