[英]Modeling class relationships in OWL
我有一个本体,代表了我对职业和学历的看法。 该模型在视觉上是这样表示的:
作为本体的一部分,我想为每个学位建立学位到职业“途径”的模型(如上图所示)。 以下是一些我要描述的示例:
到目前为止,这是我的本体:
@prefix : <http://www.test.org/jobs#> .
@prefix owl: <http://www.w3.org/2002/07/owl#> .
@prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> .
@prefix xml: <http://www.w3.org/XML/1998/namespace> .
@prefix xsd: <http://www.w3.org/2001/XMLSchema#> .
@prefix rdfs: <http://www.w3.org/2000/01/rdf-schema#> .
@base <http://www.test.org/jobs> .
<http://www.test.org/jobs> rdf:type owl:Ontology .
:hasEducationLevel rdf:type owl:ObjectProperty ;
rdfs:domain :Degree ;
rdfs:range :EducationLevel .
:hasOccupation rdf:type owl:ObjectProperty ;
rdfs:domain :Job ;
rdfs:range :Occupation .
:programOfStudy rdf:type owl:ObjectProperty ;
rdfs:domain :Degree ;
rdfs:range :ProgramOfStudy .
:requiresEducation rdf:type owl:ObjectProperty ;
rdfs:domain :Job ;
rdfs:range :Degree .
:title rdf:type owl:DatatypeProperty ;
rdfs:domain :Job ;
rdfs:range xsd:string .
:Accounting rdf:type owl:Class ;
rdfs:subClassOf :Finance .
:Audit rdf:type owl:Class ;
rdfs:subClassOf :Finance .
:BachelorsDegree rdf:type owl:Class ;
owl:equivalentClass [ owl:intersectionOf ( :Degree
[ rdf:type owl:Restriction ;
owl:onProperty :hasEducationLevel ;
owl:hasValue :BachelorsEducationLevel
]
) ;
rdf:type owl:Class
] .
:Computer_Science rdf:type owl:Class ;
rdfs:subClassOf :ProgramOfStudy .
:Degree rdf:type owl:Class .
:EducationLevel rdf:type owl:Class .
:Finance rdf:type owl:Class ;
rdfs:subClassOf :ProgramOfStudy .
:Job rdf:type owl:Class .
:Licensed_Practical_Nurse rdf:type owl:Class ;
rdfs:subClassOf :Nurse .
:MastersDegree rdf:type owl:Class ;
owl:equivalentClass [ owl:intersectionOf ( :Degree
[ rdf:type owl:Restriction ;
owl:onProperty :hasEducationLevel ;
owl:hasValue :MastersEducationLevel
]
) ;
rdf:type owl:Class
] .
:Mobile_Developer rdf:type owl:Class ;
rdfs:subClassOf :Software_Developer .
:Nurse rdf:type owl:Class ;
rdfs:subClassOf :Nursing_Occupation .
:Nurse_Manager rdf:type owl:Class ;
rdfs:subClassOf :Nursing_Occupation .
:Nursing rdf:type owl:Class ;
rdfs:subClassOf :ProgramOfStudy .
:NursingDegree rdf:type owl:Class ;
owl:equivalentClass [ owl:intersectionOf ( :Degree
[ rdf:type owl:Restriction ;
owl:onProperty :programOfStudy ;
owl:someValuesFrom :Nursing
]
) ;
rdf:type owl:Class
] .
:Nursing_Occupation rdf:type owl:Class ;
rdfs:subClassOf :Occupation .
:Occupation rdf:type owl:Class .
:ProgramOfStudy rdf:type owl:Class .
:Registered_Nurse rdf:type owl:Class ;
rdfs:subClassOf :Nurse .
:Software_Developer rdf:type owl:Class ;
rdfs:subClassOf :Occupation .
:Web_Developer rdf:type owl:Class ;
rdfs:subClassOf :Software_Developer .
:BachelorsEducationLevel rdf:type owl:NamedIndividual ,
:EducationLevel .
:MastersEducationLevel rdf:type owl:NamedIndividual ,
:EducationLevel .
我已经考虑过使用对象属性和个体,但是我不确定在为个体的对象属性指定值时如何实现通用化。
有人可以对我如何在OWL中为职业途径建立这些程度的模型提出建议吗? 谢谢。
如果Software developer
是您获得CS学位的兼容职业的最高职位,那么您将断言
Software developer
subClassOf存在具有CS degree
要阻止Nurse manager
只需要Nursing degree
(我怀疑他们需要某种管理课程吗?),您可以执行类似的操作:
Nurse manager
存在具有学位Management role
现在,没有这种学位的个人将不会被归类为Nurse manager
(潜在)。 但是,如果您断言他们是护士经理,系统将不会抱怨。
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