Observable.create（...）。map不是函数

Question

我只是学习Pluralsight-RxJS反应式编程入门

为什么不工作？

我使用RXJS 6.2.0

import {Observable} from 'rxjs';

const numbers = [1, 5, 10];
const source = Observable.create(observer => {

  let index = 0;
  let produceValue = () => {
    observer.next(numbers[index++]);

    if (index < numbers.length) {
      setTimeout(produceValue, 2000);
    } else {
      observer.complete();
    }
  };

  produceValue();

}).map(n => n * 2)
  .filter(n => n > 4);

source.subscribe(
  value => console.log(`value: ${value}`),
  e => console.log(`error: ${e}`),
  () => console.log('complete')
);

Answer 1

我在做同样的过程，并且能够使用管道并通过以下方式在箭头函数的参数中键入变量来解决此问题：

...
let source = Observable.create(observer => {

    let index = 0;
    let produceValue = () => {

        observer.next(numbers[index++]);

        if (index < numbers.length) {
            setTimeout(produceValue, 250);
        } else {
            observer.complete();
        }
    }

    produceValue();
}).pipe(
    map((n: number) => n * 2),
    filter((n: number) => n > 4)
);
...

要求在管道内部使用运算符是RxJs工作方式的最新更改，因此某些课程和参考资料可能已过时。

Answer 2

根据评论的建议，您现在应该使用管道。

您的代码已编辑：

import {Observable} from 'rxjs';
import {map, filter} from 'rxjs/operators';
const numbers = [1, 5, 10];
const source = Observable.create(observer => {

  let index = 0;
  let produceValue = () => {
    observer.next(numbers[index++]);

    if (index < numbers.length) {
      setTimeout(produceValue, 2000);
    } else {
      observer.complete();
    }
  };

  produceValue();

}).pipe(map<number, number>(n => n * 2),filter(n => n > 4)); // Here we pipe operators, you can provide any number of operators. or chain many pipe. 

source.subscribe(
  value => console.log(`value: ${value}`),
  e => console.log(`error: ${e}`),
  () => console.log('complete')
);

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