[英]Can these formulas be simplified? Why does INDIRECT function seem to not work inside an ISBLANK test within a MATCH formula?
[英]Indirect Match formula within VBA
我很难将公式加入VBA
这是公式:
=INDEX('Raw G'!1:1048576,MATCH(N5,INDIRECT("'Raw G'!" & ToColletter(MATCH(F4,'Raw G'!2:2,0))&":"&ToColletter(MATCH(F4,'Raw G'!2:2,0))),0),MATCH("Grand Total*",'Raw G'!3:3,0)+1)
我需要使用以下标准将它应用于L行下的每个单元:
Sub csku()
With Application
Set SrchRng = .Range(.Cells(4, "N"), .Cells(Rows.Count, "N").End(xlUp))
For Each cel In SrchRng
If cel.Value2 > 0 Then
cel.Offset(0, -2).Value =
End With
End Sub
但是,我不太确定该怎么做,因为它在公式中包含多个公式。
另外,我使用一个应用程序将数字转换为列字母:
Public Function ToColletter(Collet)
ToColletter = Split(Cells(1, Collet).Address, "$")(1)
End Function
非常感谢您的帮助。
对于您的公式,最好使用INDEX而不是INDIRECT。
=if(n4>0, index('Raw G'!A:XFC, match(n5, index('Raw G'!A:XFC, 0, match(f4, 'Raw G'!$2:$2, 0)), 0), match("Grand Total*", 'Raw G'!$3:$3, 0)+1), text(,))
然后将其应用于“具有以下一组标准的每个L单元中的每个单元” 。
Sub csku()
dim f as string
With worksheets("sheet1")
with .Range(.Cells(4, "L"), .Cells(Rows.Count, "N").End(xlUp).Offset(0, -2))
'double-up quotes within a quoted string
.formula = "=if(n4>0, index('Raw G'!A:XFC, match(n5, index('Raw G'!A:XFC, 0, match(f4, 'Raw G'!$2:$2, 0)), 0), match(""Grand Total*"", 'Raw G'!$3:$3, 0)+1), text(,))"
'optionally convert formula results to values
'.value = .value
end with
End With
End Sub
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