PowerShell-OR运算符

Question

我正在尝试运行此命令以获取A和CNAME记录，但它似乎不起作用，我的语法错误。 它仅检索CNAME类型的DNS记录。

实际命令是：Get-DnsServerResourceRecord -RRType“ CNAME”

$results = Get-DnsServerZone | % {
$zone = $_.zonename
Get-DnsServerResourceRecord $zone -filter {(RRType -like "CNAME") -or (RRType -like "A")}   | select @{n='ZoneName';e={$zone}}, HostName, RecordType, @{n='RecordData';e={if ($_.RecordData.IPv4Address.IPAddressToString) {$_.RecordData.IPv4Address.IPAddressToString} else {$_.RecordData.NameServer.ToUpper()}}}
}

$results | Export-Csv -NoTypeInformation c:\temp\DNSRecords10.csv -Append 

Answer 1

您应该使用Where-Object进行过滤，因为cmdlet没有自己的参数：

Get-DnsServerResourceRecord -ZoneName $zone |
    Where-Object { $_.RRType -in 'CNAME', 'A' } |
    Select-Object -Property @(
        @{ Name       = 'ZoneName'
           Expression = { $zone }
         }
        'HostName'
        'RecordType'
        @{ Name       = 'RecordData'
           Expression = {
                if ($_.RecordData.IPv4Address.IPAddressToString) {
                    $_.RecordData.IPv4Address.IPAddressToString
                } else {
                    $_.RecordData.NameServer.ToUpper()
                }
            }
         }
    )

作为一个注脚， -like是一样的使用-eq ，如果你不使用通配符。

---

说明文件：

• Get-DnsServerResourceRecord
• about_Comparison_Operators
• Where-Object

Answer 2

TheIncorrigible1提出的解决方案的替代方法是简单地发出两个查询：

@(
  Get-DnsServerResourceRecord $zone -RRType CNAME
  Get-DnsServerResourceRecord $zone -RRType A
) | select @{n='ZoneName';e={$zone}}, HostName, RecordType, @{n='RecordData';e={if ($_.RecordData.IPv4Address.IPAddressToString) {$_.RecordData.IPv4Address.IPAddressToString} else {$_.RecordData.NameServer.ToUpper()}}}