[英]combining 2 queries in one Mysql
第一个SQL查询:
SELECT COUNT(*) FROM (
SELECT
rec_business.personal_id,
rec_business.id AS id,
rec_personal.l_name AS last_name,
rec_personal.f_name AS first_name,
rec_personal.m_name AS middle_name,
rec_business.bus_name AS bus_name,
rec_business.reg_type AS reg_type,
rec_business_type.name AS buss_type,
rec_business.address AS address,
rec_business.reg_date AS reg_date,
rec_business.expire_date AS exp_date
FROM
rec_business
INNER JOIN rec_personal ON rec_business.personal_id = rec_personal.id
INNER JOIN rec_business_type ON rec_business_type.id = rec_business.bus_nature
WHERE rec_business.expire_date > NOW()
) t
第二个SQL查询:
SELECT COUNT(*) FROM (
SELECT
rec_business.personal_id,
rec_business.id AS id,
rec_personal.l_name AS last_name,
rec_personal.f_name AS first_name,
rec_personal.m_name AS middle_name,
rec_business.bus_name AS bus_name,
rec_business.reg_type AS reg_type,
rec_business_type.name AS buss_type,
rec_business.address AS address,
rec_business.reg_date AS reg_date,
rec_business.expire_date AS exp_date
FROM
rec_business
INNER JOIN rec_personal ON rec_business.personal_id = rec_personal.id
INNER JOIN rec_business_type ON rec_business_type.id = rec_business.bus_nature
WHERE rec_business.expire_date <= NOW()
) t
如何将这两个查询合二为一
这没有经过测试,但像......
SELECT
COUNT(CASE WHEN rec_business.expire_date > NOW() THEN 1 END) AS NotExpired,
COUNT(CASE WHEN rec_business.expire_date <= NOW() THEN 1 END) AS Expired,
COUNT(1) As TotalCount
FROM rec_business
INNER JOIN rec_personal
ON rec_business.personal_id = rec_personal.id
INNER JOIN rec_business_type
ON rec_business_type.id = rec_business.bus_nature
sum()
是你想要的而不是count()
的正确函数:
SELECT SUM(CASE WHEN rcb.expire_date > NOW() THEN 1 ELSE 0 END) AS NotExpired,
SUM(CASE WHEN rcb.expire_date <= NOW() THEN 1 END) AS Expired,
COUNT(1) As TotalCount
FROM rec_business rcb INNER JOIN
rec_personal rcp
ON rcb.personal_id = rcp.id INNER JOIN
rec_business_type rbt
ON rbt.id = rcb.bus_nature;
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