尝试调整尺寸时图像被拉伸以保持宽高比

Question

我使用以下代码来调整图像的大小，以保留宽高比

 public Bitmap resizeImage(System.Drawing.Image imgToResize, SizeF size)
        {
            int sourceWidth = imgToResize.Width;
            int sourceHeight = imgToResize.Height;

            float nPercent = 0;
            float nPercentW = 0;
            float nPercentH = 0;

            nPercentW = ((float)size.Width / (float)sourceWidth);
            nPercentH = ((float)size.Height / (float)sourceHeight);

            if (nPercentH < nPercentW)
                nPercent = nPercentH;
            else
                nPercent = nPercentW;

            int destWidth = (int)(sourceWidth * nPercent);
            int destHeight = (int)(sourceHeight * nPercent);

            Bitmap b = new Bitmap(destWidth, destHeight);
            Graphics g = Graphics.FromImage((System.Drawing.Image)b);

            // Used to Prevent White Line Border 

           // g.InterpolationMode = System.Drawing.Drawing2D.InterpolationMode.HighQualityBicubic;

            g.DrawImage(imgToResize, 0, 0, destWidth, destHeight);
            g.Dispose();

            return b;
        }

但是大宽度的图像会被压缩，内容似乎被压缩在一个很小的空间中。我要达到的目的是： 调整大尺寸/大分辨率图像的尺寸，因为处理此过程将花费大量时间，因此当图像的宽度或高度超过说1000我想将图像调整为较小的尺寸，例如：1000宽度或高度较大，这样我可以节省计算时间。但是，似乎上面的代码是在我试图将图像适合1000X1000 Box时强行尝试做

if (y.Width > 1000 || y.Height > 1000)
{

y = new Bitmap( resizeImage(y, new Size(1000, 1000)));

}

Answer 1

试试这个，有点整洁

public static Bitmap ResizeImage(Bitmap source, Size size)
{
   var scale = Math.Min(size.Width / (double)source.Width, size.Height / (double)source.Height);   
   var bmp = new Bitmap((int)(source.Width * scale), (int)(source.Height * scale));

   using (var graph = Graphics.FromImage(bmp))
   {
      graph.InterpolationMode = InterpolationMode.High;
      graph.CompositingQuality = CompositingQuality.HighQuality;
      graph.SmoothingMode = SmoothingMode.AntiAlias;
      graph.DrawImage(source, 0, 0, bmp.Width, bmp.Height);
   }
   return bmp;
}