[英]Upgrading a Handler with Runnable to lambda expression
我想升级此代码以使用lambda表达式:
Handler handler = new Handler(Looper.getMainLooper());
handler.postDelayed(new Runnable() {
@Override
public void run() {
missileX = ufoX;
resetRecent();
waitForUfoTimer = false;
}
}, randomize(20000, 18000));
我这样尝试,但无法编译:
Handler handler2 = new Handler(Looper.getMainLooper());
handler2.postDelayed(Runnable task = () -> {
missileX = ufoX;
resetRecent();
waitForUfoTimer = false;
}
}, randomize(20000, 18000));
在哪里有一些说明,以便我可以学习如何做? 我必须猜测语法是荒谬的。
您不必声明要分配给lambda的变量。 这就够了 :
Handler handler2 = new Handler(Looper.getMainLooper());
handler2.postDelayed(() -> {
missileX = ufoX;
resetRecent();
waitForUfoTimer = false;
}
, randomize(20000, 18000));
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