繁体   English   中英

SQL中两个表之间的比较

[英]Comparison between two tables inSQL

我想知道快照表中不存在哪种“类型”,但是总是会出现以下错误:-

Select  * FROM 
     (Select type from snapshot) AS A where date = CURDATE())
    LEFT JOIN
     (Select type from register) AS B
ON A.type=B.type
WHERE B.type IS NULL

有人可以帮帮我吗?

这是一个有效查询的示例:

SELECT a.type 
  FROM snapshot a
  LEFT 
  JOIN register b
    ON b.type = a.type
 WHERE a.date = CURDATE()
   AND b.type IS NULL
In Standard SQL Syntax:

Select  * FROM 
     (Select type from snapshot where date = CURDATE())AS A 
    LEFT JOIN
     (Select type from register) AS B
ON A.type=B.type
WHERE B.type IS NULL

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM