设置https ssl连接的客户端请求超时（相互认证）

Question

下面的代码是客户端的示例/片段，用于将json内容发布到HTTPS静态Web服务（在python中开发）。

如何设置客户端发布请求网址（https）的超时（毫秒）。 如何进行重试以多次轮询服务器ulr。 我可以在google和stackoverflow中看到有关http url服务的示例，但对于https（安全连接）则没有。 提前致谢。

import java.io.PrintStream;
import java.net.URL;
import java.security.KeyManagementException;
import java.security.NoSuchAlgorithmException;
import javax.net.ssl.HttpsURLConnection;

public class App{

     public static void main(String []args) throws NoSuchAlgorithmException, KeyManagementException{

        String https_url = "https://192.168.14.5:8989/books";
        String content = "{\"data\":{\"aaa\"}}";
        System.setProperty("javax.net.useSystemProxies", "true");

        System.setProperty("javax.net.ssl.keyStore", "C:/cert/client_cert.jks");
        System.setProperty("javax.net.ssl.keyStorePassword", "testdev");

        System.setProperty("javax.net.ssl.trustStore", "C:/cert/server_cert.jks");
        System.setProperty("javax.net.ssl.trustStorePassword", "testdev");

        System.setProperty("jdk.tls.client.protocals", "TLSv1.2");
        System.setProperty("https.protocals", "TLSv1.2");

        HttpsURLConnection.setDefaultHostnameVerifier((hostname, session) -> { return true;});
        URL url = new URL(https_url);
        HttpsURLConnection httpsCon = (HttpsURLConnection) url.openConnection();

        httpsCon.setRequestProperty("Content-Type", "application/json");
        httpsCon.setRequestMethod("POST");
        httpsCon.setDoOutput(true);
        PrintStream ps = new PrintStream(httpsCon.getOutputStream());
        ps.println(content);
        ps.close();
        httpsCon.connect();
        httpsCon.getResponseCode();
        httpsCon.disconnect();
     }
}

Answer 1

您可以使用Apache HttpClient库，通常它由REST easy或AXIS2之类的许多框架用于实现REST和SOAP传输。

例如：

 // for the retry use setRetryHandler
    CloseableHttpClient httpClient = builder.setDefaultSocketConfig(SocketConfig.custom().setSoTimeout(20000).setSoKeepAlive(true).build()).setConnectionTimeToLive(2000, TimeUnit.MILLISECONDS).build();
    HttpGet httpGet = new HttpGet("https://mypython.com");
    ResponseHandler<String> responseHandler = new BasicResponseHandler();
    String responseBody = getHttpClient().execute(httpGet, responseHandler);