过滤搜索所有键值对的对象数组

Question

假设我在JavaScript中有一个对象数组，看起来像这样：

namesArray = [
  { name: 'John', friend: 'Steve', brother: 'Jeff', sister: 'Karen'},
  { name: 'Sarah', friend: 'Joan', brother: 'Marvin', sister: 'Diana'},
  { name: 'Morris', friend: 'Tanya', brother: 'Mike', sister: 'Lisa'},
  { name: 'Brian', friend: 'Tim', brother: 'Andrew', sister: 'Tanya'},
];

如果我想将上述数组中包含“ Tanya”值的对象过滤到一个新数组中，该如何处理？ 新数组如下所示：

newArray = [
  { name: 'Morris', friend: 'Tanya', brother: 'Mike', sister: 'Lisa'},
  { name: 'Brian', friend: 'Tim', brother: 'Andrew', sister: 'Tanya'},
];

Answer 1

您正在寻找filter

 namesArray = [ { name: 'John', friend: 'Steve', brother: 'Jeff', sister: 'Karen'}, { name: 'Sarah', friend: 'Joan', brother: 'Marvin', sister: 'Diana'}, { name: 'Morris', friend: 'Tanya', brother: 'Mike', sister: 'Lisa'}, { name: 'Brian', friend: 'Tim', brother: 'Andrew', sister: 'Tanya'}, ]; const output = namesArray.filter(obj => Object.values(obj).findIndex(val => val === 'Tanya') > -1 ) console.log(output) 

Answer 2

这是一个需要Object.values （ caniuse？ ）的简短解决方案：

 var namesArray = [ { name: 'John', friend: 'Steve', brother: 'Jeff', sister: 'Karen' }, { name: 'Sarah', friend: 'Joan', brother: 'Marvin', sister: 'Diana' }, { name: 'Morris', friend: 'Tanya', brother: 'Mike', sister: 'Lisa' }, { name: 'Brian', friend: 'Tim', brother: 'Andrew', sister: 'Tanya' }, ]; var tanyaOnly = namesArray.filter(e => Object.values(e).indexOf("Tanya") > -1); console.log(tanyaOnly); 

Answer 3

使用includes会容易得多。

 const namesArray = [ { name: 'John', friend: 'Steve', brother: 'Jeff', sister: 'Karen'}, { name: 'Sarah', friend: 'Joan', brother: 'Marvin', sister: 'Diana'}, { name: 'Morris', friend: 'Tanya', brother: 'Mike', sister: 'Lisa'}, { name: 'Brian', friend: 'Tim', brother: 'Andrew', sister: 'Tanya'}, ]; let filteredArray = namesArray.filter(x => Object.values(x).includes('Tanya') === false); console.log(filteredArray);