繁体   English   中英

当说类没有接受String []的静态void主方法时,在何处添加main方法

[英]Where to add main method when it says class does not have a static void main method accepting String[]

我正在尝试使我的名为ZawTennisPlayer的程序使用构造函数和显示方法输出以下内容。 所需样品输出 我正在使用一个名为TestTennisPlayer2的示例代码来对其进行测试并获得所需的输出。 我当前的代码是:

public class ZawTennisPlayer

{
//instance variables
private String playerName;
private String country;
private int rank;
private int age;
private int wins;
private int losses;

//default constructor
public ZawTennisPlayer()
{
playerName=null;
country=null;
rank=0;
age=0;
wins=0;
losses=0;

}

//parameterized constructor
public ZawTennisPlayer(String playerName,String country)
{
this.playerName=playerName;
this.country=country;
rank=0;
age=0;
wins=0;
losses=0;

}

//parameterized constructor
public ZawTennisPlayer(String playerName,String country,int rank, int age)
{
this.playerName=playerName;
this.country=country;
this.rank=rank;
this.age=age;
wins=0;
losses=0;
}

//parameterized constructor
public ZawTennisPlayer(String playerName,String country,int rank, int age,int wins,int losses)
{
this.playerName=playerName;
this.country=country;
this.rank=rank;
this.age=age;
this.wins=wins;
this.losses=losses;

}

//all accesor and mutator method for all six fields.

public String getPlayerName()

{

return playerName;

}

public void setPlayerName(String playerName)

{

this.playerName = playerName;

}

public String getCountry()

{

return country;

}

public void setCountry(String country)

{

this.country = country;

}

public int getRank()

{

return rank;

}

public void setRank(int rank)

{

this.rank = rank;

}

public int getAge()

{

return age;

}

public void setAge(int age)

{

this.age = age;

}

public int getWins()

{

return wins;

}

public void setWins(int wins)

{

this.wins = wins;

}

public int getLosses()

{

return losses;

}

public void setLosses(int losses)

{

this.losses = losses;

}

//method to display player details
public void displayPlayer()
{

System.out.println("Player's name: " + getPlayerName());

System.out.println("Player's country: " + getCountry());

System.out.println("Player's rank: " + getRank());

System.out.println("Player's age: " + getAge());

System.out.println("Player's wins: " + getWins());

System.out.println("Player's losses: " + getLosses());

System.out.println();
}

}

但是,当该程序编译但出现错误“该类没有接受String []的静态void main方法”。 当我运行它时。 我知道我应该在ZawTennisPlayer程序中的某个位置添加一些“公共静态void main(String [] args)”,但是我不确定在哪里。 任何想法我如何可以修复程序以获得所需的输出? 提前致谢!

我用来测试程序的示例代码“ TestTennisPlayer2”是:

public class TestTennisPlayer2
{
  public static void main(String[] args)
  {
    ZawTennisPlayer tp1 = new ZawTennisPlayer();
    ZawTennisPlayer tp2 = new ZawTennisPlayer("Nick Kyrgios", "Australia");
    ZawTennisPlayer tp3 = new ZawTennisPlayer("Simona Halep", "Romania", 1, 26);
    ZawTennisPlayer tp4 = new ZawTennisPlayer("Novak Djokovic", "Serbia", 18, 30, 6, 6);

    tp1.displayPlayer();
    tp2.displayPlayer();
    tp3.displayPlayer();
    tp4.displayPlayer();




  }
}

如在评论中提到的,看来你尝试运行ZawTennisPlayer哪里,你应该运行TestTennisPlayer2
如果您通过命令提示符运行,请使用

>javac TestTennisPlayer2.java

>java TestTennisPlayer2 

或从Eclipse IDE中,

open TestTennisPlayer2.java, right click -> run as > java application

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM