[英]How to iterate over the following array of objects inside another object in Javascript?
[英]How to group an array of objects by another object inside in javascript
我正在尝试创建一个函数,以将某个区域的排列元素分组,这将是原始数组。
一些细节:
数组中的某些元素没有区域。
如果没有相等的区域,则将其包括在内。
该区域不能重复,也就是说,如果元素没有包含元素的区域,并且元素有没有包含的区域,而该区域不重复。
这是数组的示例:
有些元素没有这样的区域:
{_id: "455", name: "ALBACETE"}
并且有带区域的元素:
{zone: {_id: "zone1", name: "zone1"}, _id: "143", name: "ALCALA"}
{zone: {_id: "zone1", name: "zone1"}, _id: "144", name: "OTRO"}
{zone: {_id: "zone2", name: "zone2"}, _id: "144", name: "OTRO MAS"}
对于此示例,需要的是以下结果:
{_id: "455", name: "ALBACETE"}
{zone: {_id: "zone1", name: "zone1"}, _id: "143", name: "ALCALA"}
{zone: {_id: "zone2", name: "zone2"}, _id: "144", name: "OTRO MAS"}
任何帮助表示赞赏!
这应该帮助不是最干净的代码,但是...
const q = [
{ zone: { _id: "zone1", name: "zone1" }, _id: "143", name: "ALCALA" },
{ zone: { _id: "zone1", name: "zone1" }, _id: "144", name: "OTRO" },
{ zone: { _id: "zone2", name: "zone2" }, _id: "144", name: "OTRO MAS" },
{ _id: "455", name: "ALBACETE" }
];``
let ret = [];
let result = q.filter( x => {
if(!ret.includes(x._id)) {
ret.push(x._id);
return true;
}
return false;
});
console.log (result);
输出将是
[
{ zone: { _id: 'zone1', name: 'zone1' }, _id: '143', name: 'ALCALA' },
{ zone: { _id: 'zone1', name: 'zone1' }, _id: '144', name: 'OTRO' },
{ _id: '455', name: 'ALBACETE' }
]
根据您的要求。
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