MySQL 使用 max(date) 和 sum 获取 val

Question

这是我的问题。 我有一个包含以下列的表格：

player_id | win_amount | loss_amount | datetime

每条记录都包含玩家的 id、输赢金额（另一个字段变为 0）和日期时间。 我想要一个 MySQL 查询来获得以下信息：

• player_id
• sum(win_amount) - sum(loss_amount)该玩家的sum(win_amount) - sum(loss_amount)
• 有非零loss_amount最后日期loss_amount
• 前一个日期时间的loss_amount

Answer 1

尝试以下查询，利用GROUP BY 、一些聚合函数和相关子查询。 将table替换为您的实际表名：

SELECT 
    t1.player_id,
    SUM(t1.win_amount) - SUM(t1.loss_amount) AS net_win_amount,
    MAX(IF(t1.loss_amount > 0,
        t1.datetime,
        NULL)) AS last_loss_datetime,
    (SELECT 
            t2.loss_amount
        FROM
            `table` AS t2
        WHERE
            t2.player_id = t1.player_id
                AND t2.loss_amount > 0
        ORDER BY t2.datetime DESC
        LIMIT 0 , 1) AS last_loss_amount
FROM
    `table` AS t1
GROUP BY t1.player_id